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Bogdan [553]
3 years ago
8

Please help me

Physics
1 answer:
g100num [7]3 years ago
5 0

Answer:

0.3956

Explanation:

Newton's 2nd law of motion says that Force = Mass*Acceleration (f=ma) so to find the force used on the football you multiply it's mass by its acceleration.

0.43*0.92 = 0.3956.

0.4 if you round

You might be interested in
A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it wi
Free_Kalibri [48]

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A =  \sqrt{\frac{1.25\  \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

6 0
3 years ago
Consider the previous situation. Under what condition would the acceleration of the center of mass be zero? Keep in mind that F1
Nana76 [90]

Answer:

a) m₁ = m₂  F₁ₓ = F₂ₓ

b) m₁ << m₂   F₂ₓ =0

Explanation:

This interesting exercise is unclear your statement, so that in a center of mass system has an acceleration of zero it is necessary that the sum of the forces on each axis is zero, to see this we write Newton's second law

     ∑ F = m a

for acceleration to be zero implies that the net force is zero.

we must write the expression for the center of mass

        x_{cm} = 1 / M (m₁ x₁ + m₂ x₂)

now let's use the derivatives

      a_{cm} = d² x_{cm}/dt² = 1 / M (m₁ a₁ + m₂a₂)

where M is the total mass M = m₁ + m₂

     so that the acceleration of the center of mass is zero

               0 = 1 / M (m₁ a₁ + m₂a₂)

               m₁ a₁ = - m₂ a₂

In the case that we have components on the x axis, the modulus of the two forces are equal and their direction is opposite, therefore

   F₁ₓ = -F₂ₓ

b)r when the two masses are equal , in the case of a mass greater than the other m₁ << m₂

      acm = d2 xcm / dt2 = 1 / M (m1 a1 + m2a2)

so that the acceleration of the center of mass is zero

               0 = 1 / M (m1 a1 + m2a2)

               m1 a1 = - m 2 a2

with the initial condition, we can despise m₁, therefore

                0 = m₂a₂

 if we use Newton's second law

              F₂ = 0

       

I tell you that in this case with a very high mass difference the force on the largest mass must be almost zero

4 0
3 years ago
You're driving down the highway late one night at 22 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
sleet_krkn [62]

speed of the car is given on the road

v = 22 m/s

reaction time is given as

t = 0.50 s

now we can find the distance that it will move during this reaction time

d_1 = 22* 0.50 = 11 m

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

v_f^2 - v_i^2 = 2 a d

0^2 - 22^2 = 2*(-10)*d

d = 24.2 m

so the total distance that it require to stop is given as

d = 24.2 + 11 = 35.2 m

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer


3 0
3 years ago
2. Above right: The four positions of the thrown ball with no gravity are
padilas [110]

The characteristics of the projectile launch allows to find the results for the questions about the movement of the ball are:

  • In the attached we see the vertical speed decreases with height and the curve is of the parabolic type.
  • In the movement is several dimensions, each one is independent of the others, the movement in the x axis does not affect the movement in the y axis.

Kinematics studies the motion of bodies looking for relationships between position, velocity and acceleration. In the case of vertical and projectiles launch  the acceleration on the vertical axis is the acceleration of gravity directed downward.

In the attachment we can see the position of the ball for two distances in the case of projectile launching.

We can see that the speed of the ball decreases with height according to the relation

          y = go t - ½ g t²

Where y is the height, g is the initial vertical velocity, g is the acceleration of gravity and t is time.

In all movements in various dimensions we assume that each movement in an . axis is independent

In the case of projectile launching, on the vertical axis there is an acceleration of gravity and on the horizontal axis there is no acceleration, the only parameter that this gives the two movements is the time, which is a scalar.

In conclusion, using the characteristics of the projectile launch, we can find the results for the questions about the movement of the ball are:  

  • In the movement is several dimensions, each one is independent of the others, the movement in the x axis does not affect the movement in the y axis.
  • In the attached we see the vertical speed decreases with height and the curve is of the parabolic type.

Learn more about projectile launch here: brainly.com/question/24888457

4 0
2 years ago
I NEED HELP ASAP WHAT IS THE DISTANCE MOVED IN 15 SECONDS
Oduvanchick [21]

Answer:

5 I think

Explanation:

8 0
2 years ago
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