Question

- ( 6w - 1 ) + 3 ( w - 4 )

Answer 1

So to solve your question, we can use this: 

$\sf{a(b-c) = ab-ac}$
$\sf{a(b+c) = ab+ac}$

So then 

$\sf{-(6w-1)}$

If we use the above formulas then:
$\sf{-(6w-1) = -6w+1}$

And for
$\sf{3(w-4)}$

We will get:

$\sf{3(w-4) = 3w-3(4) =3w-12}$

And to simplify
$\sf{-(6w-1)+3(w-4)}$

Since we already calculated the individual parts, not put them together, so:

$\sf{-6w+1+3w-12}$

Now we have to add the like terms which are -6w and 3w. And also 1 and -12.

Rearranging the terms, we get:

$\sf{-6w+3w-12+1}$

And $\sf{-12+1=-11}$

And also $\sf{-6w+3w= w(-6+3) = w(-3) = -3w}$

So combining that, we get:

$\sf{-3w-11}$

Which is your final answer :)