Answer:
Momentum is 100 kg.m/s
Explanation:
given
mass, m = 5 kg
velocity, v = 20 m/s
To find : momentum (P)
We know that momentum is given by equation:
p = mv
= 5 kg x 20 m/s
= 100 kg.m/s
Complete question:
A college dormitory room measures 14 ft wide by 13 ft long by 6 ft high. Weight density of air is 0.07 lbs/ft3. What is the weight of air in it under normal conditions?
Answer:
the weight of the air is 76.44 lbs
Explanation:
Given;
dimension of the dormitory, = 14 ft by 13 ft by 6 ft
density of the air, = 0.07 lbs/ft³
The volume of the air in the dormitory room = 14 ft x 13 ft x 6 ft
= 1092 ft³
The weight of the air = density x volume
= 0.07 lbs/ft³ x 1092 ft³
= 76.44 lbs
Therefore, the weight of the air is 76.44 lbs
Answer:
Explanation:
Height Of the watermelon when it is dropped is given as
time of fall under gravity
now if water melon start from rest then we have
acceleration due to gravity for watermelon
now we need to find the final speed of watermelon
so we will have
