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iris [78.8K]
3 years ago
13

5g of sugar is dissolved in "50g" of water what is the mass of the sugar water

Physics
2 answers:
n200080 [17]3 years ago
7 0

Answer:   55 g

Explanation:

Given : Mass of sugar dissolved in water = 5g

i.e. Mass of solute = 5 g

Mass of water in solution = 50 g

i.e. Mass of solvent = 50 g

Then the mass of the the sugar water (Sugar solution)=\text{Mass of solute +Mass of solvent }

i.e. the mass of the the sugar water= \text{5 g + 50 g = 55 g}

hence, the mass of the sugar water = 55 g

polet [3.4K]3 years ago
4 0

55g because you would still have the weight of the sugar but it combines with the liquid and spreads out into the water.

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Which type of thermal energy transfer warms your hand when you hold it near a glass of hot water?
NeTakaya

Answer: the answer is radiation

Explanation: Radiation, because heat travels in all directions Convection, because heat travels in all directions Conduction, because heat travels from hot to cold Radiation, because heat travels from cold to hot.

8 0
3 years ago
The company where you work has obtained and stored five lasers in a supply room. You have been asked to determine the intensity
VikaD [51]

Answer:

a)  I = 5.79 10⁵ W/m² , b)  I = 2.58 10² W / m², c)   I = 8.03 10³ W / m² , d)     I = 5.3 10⁶ W / m², e)  I = 9 10¹ W / m² , f)  D> A> C> B> E

Explanation:

The intensity is defined as the power per unit area

       I = P / A

The area of ​​a circle is

      A = π r²

Laser A

Power P = 2.2 W

Diameter d = 2.9 mm = 2.9 10⁻³ m

Let's calculate

Area

      A =  π d² / 4

     A =  π (2.2 10⁻³)²/4

     A = 3.80 10⁻⁶ m²

Let's calculate the intensity

     I = 2.2 / 3.80 10⁻⁶

     I = 0.579 10⁶ W / m²

     I = 5.79 10⁵ W/m²

Laser B

The electric field is E = 440 V / m

Intensity average is

      I = E B / 2 μ₀

The relationship of the fields with the speed of light

      E / B = c

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       I = EE / 2 μ₀ c

       I = 440² / (2 4π 10⁻⁷ 3 10⁸)

      I = 1.936 105/750

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Laser C

The magnetic field amplitude B = 8.2 10⁻⁶ T

      I = c / 2μ₀  B²

      I = 3 10⁸/2 4π 10⁻⁷ (8.2 10⁻⁶)²

      I = 8.03 10³ W / m²

Part D

Diameter d = 1.8 mm = 1.8 10⁻³ m

The radius is r = d / 2 = 0.9 10⁻³ m

The force is F = 9.0 10⁻⁸ N

The radiation pressure is on a reflective surface is

         P = 2S / c

         I = S =P c / 2

The definition of pressure is

         P = F / A

          I = F c / 2 A

          I = 9.0 10⁻⁸ 3 10⁸ / (2π (0.9 10⁻³)²)

          I = 5.3 10⁶ W / m²

Part E

Average energy density

         u = 3.0 10⁻⁷ J / m³

          I = S = c u

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Part F

Sort in descending order

The order is

  D> A> C> B> E

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3 years ago
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\huge\mathfrak\red{✔Answer:-}

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3 years ago
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Explanation:

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<u>for the first one</u><u>:</u><u> </u>

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f=m2×a

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8 0
4 years ago
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Answer:

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7 0
3 years ago
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