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iris [78.8K]
2 years ago
13

5g of sugar is dissolved in "50g" of water what is the mass of the sugar water

Physics
2 answers:
n200080 [17]2 years ago
7 0

Answer:   55 g

Explanation:

Given : Mass of sugar dissolved in water = 5g

i.e. Mass of solute = 5 g

Mass of water in solution = 50 g

i.e. Mass of solvent = 50 g

Then the mass of the the sugar water (Sugar solution)=\text{Mass of solute +Mass of solvent }

i.e. the mass of the the sugar water= \text{5 g + 50 g = 55 g}

hence, the mass of the sugar water = 55 g

polet [3.4K]2 years ago
4 0

55g because you would still have the weight of the sugar but it combines with the liquid and spreads out into the water.

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A tugboat tows a ship with a constant force of magnitude F1. The increase in the ship's speed during a 10 s interval is 3.0 km/h
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Answer:

The magnitude of F₁ is 3.7 times of F₂

Explanation:

Given that,

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Using formula of acceleration

a_{1}=\dfrac{v}{t}

a_{1}=\dfrac{0.833}{10}

a_{1}=0.083\ m/s^2

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F_{2}=ma_{2}

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F_{3}=F_{2}+F_{1}

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The speed of second tugboat is

v=\dfrac{11\times10^{3}}{3600}

v=3.05\ m/s

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a_{3}=\dfrac{v}{t}

a_{3}=\dfrac{3.05}{10}

a_{3}=0.305\ m/s^2

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0.305=a_{2}+0.083

a_{2}=0.305-0.083

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Dividing force F₁ by F₂

\dfrac{F_{1}}{F_{2}}=\dfrac{m\times0.83}{m\times0.22}

\dfrac{F_{1}}{F_{2}}=3.7

F_{1}=3.7F_{2}

Hence, The magnitude of F₁ is 3.7 times of F₂

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3 years ago
In a river, sediment is deposited _____. on the inside bends on the outside bends by fast moving water by oxbows
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Hey There!

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3 years ago
An object with a mass of 1500 g (grams) accelerates 10.0 m/s2 when an
masya89 [10]

Answer:

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An elevator together with its passengers weights 5000 N. At a certain instant, the tension in its supporting cable is 6000 N. De
gayaneshka [121]
We have to forces acting on the system (elevator+passengers):
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a= \frac{F}{m}
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So, we need to find F and m.
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To find m, we can use the weight of the system. In fact, the weight of an object is given by
W=mg
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m= \frac{W}{g}= \frac{5000 N}{9.81 m/s^2}=510 kg

and at this point, we can calculate the acceleration of the system (elevator+people):
a= \frac{F}{m}= \frac{1000 N}{510 kg}=1.96 m/s^2
and the acceleration has the same direction of the resultant force, so upward.
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