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scoundrel [369]

2 years ago

5

How many quarters are in a jar of quarters worth $9.75?

2 answers:

grigory [225]2 years ago

6 0

Answer:

39

Step-by-step explanation:

quarters are worth $.25. just divide 9.75 by .25 and you get your answer.

9.75 ÷ .25 = 39

Kobotan [32]2 years ago

6 0

Answer:

39

Step-by-step explanation:

39 x 25 = 975

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Sam started a dog-walking business. He charges $5 for each dog for a thirty-minute walk. How much dor

solong [7]

Answer: $\$10,\ \$5$

Step-by-step explanation:

(a) Given

Sam charge $5 for each dog for a thirty minute walk

For an hour which is double the thirty minutes, it must be double of the same charge.

$\Rightarrow 2\times 5=\$10$

(b)Given

With $20, Christie sells 100 cups of lemonade with a quarter per cup charge

For 100 cup, she generate a revenue of

$\Rightarrow \dfrac{1}{4}\times 100\\\\\Rightarrow \$25$

So, she earns $25-20=\$5$ that is , her profit is $\$5$

7 0

2 years ago

Hello, I need help with this math problem please

Marina86 [1]

Answer:

4c^2+7c-5=0

4c^2+7c=5

4c^2+7c=5

4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)

Hope This Helps!!!

4 0

2 years ago

Read 2 more answers

Unit 3 homework 2 geometry

ioda

Where is the question?

6 0

2 years ago

Solve the equation 23(9+x)=−5(4−x).

NemiM [27]

Answer:

x= $-\frac{277}{18}$

Step-by-step explanation:

7 0

2 years ago

Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).

Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>

The critical points of a function are the values of x for which:

$f^{\prime}(x) = 0$

In this problem, the function is:

$f(x) = x^3 + ax^2 + b$

Hence, the derivative is:

$f^{\prime}(x) = 3x^2 + 2ax$

Then:

$f^{\prime}(x) = 0$

$3x^2 + 2ax = 0$

$x(3x + 2a) = 0$

$x = 0$

$3x + 2a = 0$

$3x = -2a$

$x = -\frac{2a}{3}$

Since the critical point is at x = 2, we have that:

$-\frac{2a}{3} = 2$

$-2a = 6$

$2a = -6$

$a = -3$

Then:

$f(x) = x^3 - 3x^2 + b$

Critical point at (2,3) means that when $x = 2, y = 3$ , then:

$3 = 2^3 - 3(2)^2 + b$

$8 - 12 + b = 3$

$b = 7$

You can learn more about the critical point concept at brainly.com/question/2256078

4 0

1 year ago