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2 years ago

Word Bank: Match each term with the sentence below

Chemistry

1 answer:

Ymorist [56]2 years ago

3 0

Answer:

Electromagnetic Wave Medium Matter:The ability to move or change an object, or what a wave

Longitudinal Wave Trough Rarefaction: The area in a longitudinal wave where the particles are close together.

Transverse Wave Energy Wavelength: The highest point of a transverse wave

Explanation:

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Aerosol cans have a label that warns the user not to use them above a certain temperature and not to dispose of them by incinera

Alex73 [517]

Answer:

1.40 atm

Explanation:

To answer this question we can use Gay-Lussac's law, which states:

P₁T₂=P₂T₁

When volume and number of moles remain constant.

P₁ = 1.11 atm

T₁ = 23°C ⇒ 23+273.16 = 296.16 K

T₂ = Boiling point of water = 100 °C ⇒ 100+273.16 = 373.16 K

P₂ = ?

We put the known data in the equation and solve for P₂:

1.11 atm * 373.16 K = P₂ * 296.16 K

P₂ = 1.40 atm

4 0

2 years ago

The highest point on a wave is the ______ while the lowest point is the ____

Mkey [24]

The highest point = crest

lowest point = trough

4 0

3 years ago

PLEASE HELP!!!

neonofarm [45]

Answer:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

$Cl_2+NaI\rightarrow I_2+NaCl$

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Best regards!

8 0

2 years ago

Predict what might happen if the human body did not have specialized cells, tissues, organs, and organ systems to maintain homeo

bekas [8.4K]

We would be dead. No heart, brain or blood flow

3 0

3 years ago

Read 2 more answers

Calculate the freezing point (in degrees C) of a solution made by dissolving 7.99 g of anthracene{C14H10} in 79 g of benzene. Th

mario62 [17]

Answer: The freezing point of solution is 2.6°C

Explanation:

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\Delta T_f=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

$\Delta T_f$ = $\text{Freezing point of pure solution}-\text{Freezing point of solution}$

Freezing point of pure solution = 5.5°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point depression constant = 5.12 K/m = 5.12 °C/m

$m_{solute}$ = Given mass of solute (anthracene) = 7.99 g

$M_{solute}$ = Molar mass of solute (anthracene) = 178.23 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 79 g

Putting values in above equation, we get:

$5.5-\text{Freezing point of solution}=1\times 5.12^oC/m\times \frac{7.99\times 1000}{178.23g/mol\times 79}\\\\\text{Freezing point of solution}=2.6^oC$

Hence, the freezing point of solution is 2.6°C

8 0

3 years ago