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Sophie [7]
3 years ago
11

Fatty acids are released from adipocytes when: a. insulin levels are high. b. glycerol-3-phosphate levels are high. c. adipose A

TP levels are high. d. blood glucose levels are low. e. none are true.
Chemistry
1 answer:
vitfil [10]3 years ago
7 0

Answer:

D) blood glucose levels are low

Explanation:

When glucose levels are low, glucagon levels increase. The glucagon will then bind to receptors on the adipose cells' surface, thus setting off further reactions which culminates in fatty acids being released from the cells. They will then flow through the circulatory system, where they will either bind to a protein in blood or be used by muscle tissue for energy.

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What is the definition of an independent and dependent variable?
sladkih [1.3K]

Answer:

The Independent variable is the variable which does not rely of the other variables. It stays the same.

The Dependent variable is the variable that is measured or changed.

Explanation:

The Independent variable is usually the x value of a table or graph

the Dependent variable is usually the y value of a table or graph

I hope this helps!

3 0
4 years ago
If a 600 gram radioactive sample goes through 3 half-lives, how would be left?
olga_2 [115]

Answer:

75 g

Explanation:

1 half life = 600/2 = 300g

2 half life = 300/2 = 150g

3 half life = 150/2 = 75g

5 0
3 years ago
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Flauer [41]

Answer: a for the first one , d for the second  one, b for the third one.

Explanation:

5 0
3 years ago
Read 2 more answers
The human body needs at least 1.03 x 10-^2 mol O2 every minute. If all of this oxygen is used for the
Neko [114]
<h3>Answer:</h3>

0.3093 g of glucose are consumed each minute by the body.

<h3>Explanation:</h3>
  • During cellular respiration glucose is broken down in presence of oxygen to yield energy, water and carbon dioxide.
  • The equation for the reaction taking place during cellular respiration is;

C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂

We are required to calculate the amount of glucose in grams;

<h3>Step 1: Calculate the moles of glucose broken down</h3>

From the equation, the mole ratio of glucose to Oxygen is 1 : 6

Moles of Oxygen in a minute is 1.03 × 10^-2 moles

Therefore, moles of glucose will be;

= (1.03 × 10^-2)÷6

= 1.717 × 10^-3 moles

<h3>Step 2: Mass of glucose </h3>

Mass is given by multiplying the number of moles with molar mass

mass = moles × molar mass

Molar mass glucose is 180.156 g/mol

Therefore;

Mass = 1.717 × 10^-3 × 180.156 g/mol

         = 0.3093 g

Hence, 0.3093 g of glucose are consumed each minute by the body.

3 0
4 years ago
The ratio of the heights 1.50 m and 75 cm of two persons can be written as ​
Blizzard [7]

Answer:

The required ratio would be 2:1

8 0
3 years ago
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