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frutty [35]
3 years ago
7

What is a well-tested, explanation that unifies a broad range of observations and hypotheses

Chemistry
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

The scientific Theory

Explanation:

antoniya [11.8K]3 years ago
3 0
Scientific theory is that
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Suppose Gabor, a scuba diver, is at a depth of 15m15m. Assume that: The air pressure in his air tract is the same as the net wat
alexandr1967 [171]

Answer:

The ration of molar concentration is "2.5".

Explanation:

The given values are:

Average density of salt water,

= 1.03 \ g/cm^3

Net pressure,

= 2.00 \ atm

Increase in pressure,

= 1.00 \ atm

Now,

The under water pressure will be:

=  \frac{15 \ m}{10}\times 1 \ atm +1 \ atm

=  1.5\times 1+1

=  1.5+1

=  2.5 \ atm

hence,

The ratio will be:

=  \frac{(\frac{n}{V})_{15m} }{(\frac{n}{V})_{surface} }

or,

=  \frac{P}{P_s}

=  \frac{2.5}{1}

=  2.5

7 0
3 years ago
Express the following in regular notation:
dusya [7]
A because if you multiple it, you will be moving the decimal one time
8 0
3 years ago
How many milliliters of 5.0 M NaOH are needed to exactly neutralize 40. milliliters of 2.0 M HCl?
zubka84 [21]

Answer:

16mL

Explanation:

Using the following formula;

CaVa = CbVb

Where;

Where

Ca = concentration/molarity of acid (M)

Va = volume of acid (mL)

Cb = concentration/molarity of base (M)

Vb = volume of base (mL)

According to the information provided in this question;

Ca (HCl) = 2M

Cb (NaOH) = 5M

Va (HCl) = 40mL

Vb (NaOH) = ?

Using CaVa = CbVb

Vb = CaVa/Cb

Vb = 2 × 40/5

Vb = 80/5

Vb = 16mL

5 0
2 years ago
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
lesya692 [45]
<span>Mol is the unit of amount of substance. It is equal to 6.02 x 10^23 molecules. Now, One mol of Sodium chloride (NaCl) contains 6.022x 10^23 molecules of NaCl. Also, the number atoms of both Na (sodium) and Cl (chlorine) will be equal. Similatly, One mol of Aluminium Chloride (AlCl3) contains 6.022x 10^23 molecules of (AlCl3) but the ratio of Al and Cl atoms will be 1:3</span>
7 0
3 years ago
Which combination(s) of alkyl bromide and carbonyl compound can be used to prepare the following product by reaction of the Grig
Fiesta28 [93]

Answer:

D. only 2 and 3

Explanation:

The Grignard compound or reagent is a highly reactive compound formed from the reaction between an ether solvent containing magnesium and a haloalkane. This compound can also be used to create a C-C bond (carbon-carbon). Based on the properties and structure of a Grignard compound, the answer is option D.

7 0
3 years ago
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