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frozen [14]
2 years ago
8

After Eris was discovered, scientists had to decide whether to count it as a planet. Why did this make them question whether Plu

to should still be counted as a planet?
a
because Pluto and Eris are both space objects
b
because Pluto and Eris were discovered at the same time
c
because Pluto and Eris are very different
d
because Pluto and Eris are very similar
Chemistry
1 answer:
sergey [27]2 years ago
7 0

Answer:

After Eris was discovered, they had to decide whether Eris was a planet or not. If they decided it wasn't a planet, they had to also decide whether Pluto should be counted as a planet since Eris and Pluto were quite similar. They were the same size, and they were both part of the Kuiper Belt.

Explanation:

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Mars2501 [29]

Explanation:

  1. area of rectangle=l×b
  • 15=5×b
  • b=3cm

2.area of rectangle=l×b

  • 28=l×4
  • l=7cm

3. perimeter of square=4×L

  • 24=4×L
  • L=6cm

4. perimeter of rectangle=2(L+b)

  • 14=2(4+b)
  • 14=8+2b
  • 2b=6
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hope it helps.

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2 years ago
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The weak acid HA is 5 % ionized (dissociated) in a 0.35 M solution.
ddd [48]

Answer:idk

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3 years ago
A solution of water (kf=1.86 ∘c/m) and glucose freezes at − 2.15 ∘c. what is the molal concentration of glucose in this solution
Reil [10]
<span>1.16 moles/liter The equation for freezing point depression in an ideal solution is ΔTF = KF * b * i where ΔTF = depression in freezing point, defined as TF (pure) â’ TF (solution). So in this case ΔTF = 2.15 KF = cryoscopic constant of the solvent (given as 1.86 âc/m) b = molality of solute i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1. Solving for b, we get ΔTF = KF * b * i ΔTF/KF = b * i ΔTF/(KF*i) = b And substuting known values. ΔTF/(KF*i) = b 2.15âc/(1.86âc/m * 1) = b 2.15/(1.86 1/m) = b 1.155913978 m = b So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
7 0
3 years ago
Question 10 How many oxygen atoms are in the chemical formula Al(PO4)3? O 1 O 12 O 3​
Basile [38]
13 atoms are in the chemical formula AI(PO4)3
hope that helps :-)
5 0
2 years ago
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Which of the following lists contain only elements?
N76 [4]
In which elements are belonging to? I will grant that option B ; ti's the best answer.
                 In which thou might contain the elements zinc , gold , aluminium , and last by not least oxygen.

I truly hope ti's answer helps thou. 
7 0
3 years ago
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