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valentinak56 [21]
3 years ago
11

What if you measured 15cc of liquid elemental mercury, how much would that weigh in pounds

Chemistry
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

0.447 pounds

Explanation:

The density of Mercury in grams/mL is 13.55 - I multiplied that by the volume and got approximately 203.25 grams, I then turned it into Kilograms and multiplied by 2.2 lbs / kg.

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What is the kinetic energy of a 2kg rabbit hopping at a speed of 1.25 m/s
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Answer:

What is the kinetic energy of a 2kg rabbit hopping at a speed of 1.25 m/s?1,5625J

6 0
3 years ago
Suggest the stable ion for phosphorus and why?
Darya [45]

Phosphorous has 5 valence electrons and so gaining 3 electrons will make it isoelectronic with the stable noble gas argon, and will produce the P3- ion

6 0
2 years ago
Difference between vegetative and reproductive part​
andrezito [222]

Answer:

The vegetative parts includes the roots, stems,leaves and the reproductive parts include flowers. ... The vegetative parts can reproduce new plants by the process of vegetative propagation but the reproductive parts cannot produce new plants directly instead they produce precursor of new plants that are seeds or fruits.

8 0
3 years ago
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An object that has a height of 0.4 meter is placed at a distance of 0.7 meter from a concave spherical mirror. An image is forme
julia-pushkina [17]

Answer: B. 0.6125 m

For spherical concave mirror:

Height of the object, h_o=0.4\hspace{1mm}m

Height of the image, h_i=0.35\hspace{1mm}m

Object distance, u=-0.7 m

we need to find the distance of the image, v.

These are related by the following formula:

\frac{h_i}{h_o}=-\frac{v}{u}\\ \Rightarrow v=u\times\frac{h_i}{h_o}

Insert the values:

v=-(-0.7\times\frac{0.35}{0.4})=0.6125\hspace{1mm}m

Hence, option B is the correct.


8 0
3 years ago
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In the reaction _Al 3O2→2Al2O3, what coefficient should be placed in front of the Al to balance the reaction? 1 2 3 4.
luda_lava [24]

Answer:

D.) 4

Explanation:

Al + 3 O₂ --> 2 Al₂O₃

In the equation, there are:

<em>Reactants:</em> 1 Al and 6 O

<em>Products:</em> 4 Al and 6 O

To determine how many atoms there are of each, you multiply the coefficients by the subscripts attached to the atoms. While the question doesn't ask, as you can see, the oxygen atoms are balanced because there is an equal amount on both sides. To balance the aluminum atoms, you can get 4 aluminum atoms on the reactants side by using a coefficient of 4.

The new equation would look this this:

4 Al + 3 O₂ --> 2 Al₂O₃

There are now:

<em>Reactants:</em> 4 Al and 6 O

<em>Products:</em> 4 Al and 6 O

4 0
2 years ago
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