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natulia [17]
3 years ago
13

WILL GIVE 100 POINTS PLEASE HELP EMERGENCY NEED CORRECT ANSWERS

Chemistry
2 answers:
Goryan [66]3 years ago
7 0

Answer:

<u><em>6. 13.8 moles </em></u>

<u><em> 7. 0.751 moles </em></u>

<u><em> 8. 2.04 moles </em></u>

<u><em> 9. 0.00794 moles </em></u>

<u><em> 10. 0.158 moles</em></u>

Explanation:

zubka84 [21]3 years ago
3 0

Answer:

6. 13.8 moles

7. 0.751 moles

8. 2.04 moles

9. 0.00794 moles

10. 0.158 moles

Explanation:

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M=11.20 g
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w-?

m(Mg)=wm
m(Zn)=(1-w)m

Zn + 2HCl = ZnCl₂ + H₂
m₁(H₂)=M(H₂)m(Zn)/M(Zn)=M(H₂)(1-w)m/M(Zn)

Mg + 2HCl = MgCl₂ + H₂
m₂(H₂)=M(H₂)m(Mg)/M(Mg)=M(H₂)wm/M(Mg)

m(H₂)=m₁(H₂)+m₂(H₂)
m(H₂)=M(H₂)(1-w)m/M(Zn)+M(H₂)wm/M(Mg)=M(H₂)m{(1-w)/M(Zn)+w/M(Mg)}

m(H₂)=M(H₂)m{(1-w)/M(Zn)+w/M(Mg)}

(1-w)/M(Zn)+w/M(Mg)=m(H₂)/{M(H₂)m}

1/M(Zn)-w/M(Zn)+w/M(Mg)=m(H₂)/{M(H₂)m}

w(1/M(Mg)-1/M(Zn))=m(H₂)/{M(H₂)m}-1/M(Zn)

w=[m(H₂)/{M(H₂)m}-1/M(Zn)]/(1/M(Mg)-1/M(Zn))

w=0.583 (58.3%)
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20.00 mL of a 0.077 M solution of silver nitrate, AgNO3
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N= m/v n=0.077/.200 = 0.385
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