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Nana76 [90]
3 years ago
14

Help pls!!! The radius of a circle is 15 inches. Enter the area of the circle, in square inches. Round your answer to the neares

t tenth and use 3.14 for π.
square inches
Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

706.5 inches squared

Step-by-step explanation:

The formula for the area of a circle is pi r^2. r being the radius. Because you have the radius, and pi is 3.14 in this case, your new formula is A=3.14(15)^2. 15 squared is 225, times 3.14 gives you 706.5

Your final answer is already in tenths so you don't need to round! Hope this helps :)) and brainliest is always appreciated

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Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
3 years ago
Read 2 more answers
Find a number which when divided by 3 gives the quotient 20 and remainder
Westkost [7]

Solution:

<em>the</em><em> </em><em>answer</em><em> </em><em>please</em><em> </em><em>mark</em><em> </em><em>as</em><em> </em><em>brainly ness</em><em> </em>

<em>your</em><em> </em><em>welcome</em>

8 0
2 years ago
Braden is hiking on a mountain. At 11:00 a.M., he is at an elevation of 500 feet. At 2:00 p.M., he is at 900 feet. What is the r
kramer

Answer:

133.33ft/hr

Step-by-step explanation:

Between 11am and 2pm, he had 3hrs

Height change 900 - 500 = 400ft

400/3 = 133.33ft/hr

3 0
3 years ago
A toy rocket is launched from the ground straight upward. The height of the rocket above the ground, in feet, is given by the eq
Oksanka [162]

Answer:

Although strictly speaking of mathematics i.e. theoritically,  

t

can take any value from  

{ − ∞ , ∞ ] ,

however, it is essentially a physical problem related to Physics and we cannot have negative  

t  i.e.  t ≥ 0

Further, after the maximum is reached at  t = 2  (observe that first differential is  h ' ( t ) = − 32 t + 64 , which is zero at  t = 2  and second derivative  h ' ' ( t ) = − 32  is negative and at this we have  h ( 2 ) = 64 ), at  t = 4 ,  h ( 4 ) = 0  i.e. toy rocket falls back to the ground and as such, we cannot have  h > 4 .

Hence, domain for  t  is  [ 0 , 4 ] .

tbh google

8 0
3 years ago
Write 90 as a product of primes.<br> Use index notation where appropriate.
Iteru [2.4K]

Answer:

2 × 3 × 3 × 5

Step-by-step explanation:

2 x 3 = 6

            6 x 3 = 18

                         18 x 5 = 90

7 0
3 years ago
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