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Sindrei [870]
2 years ago
7

I will do anything just no fake answers please

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
5 0

Answer:

it's b

Step-by-step explanation:

the reason it's b is because conduction happens when something hot comes in contact with something cold which heats the cold thing up and cooling the hot thing eventually they will both be room temperature

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Solve this equation: -88=5y-13
nadya68 [22]

Answer:

y=-15

Step-by-step explanation:

4 0
3 years ago
What is the justification for each step in solving the inequality?
Nuetrik [128]

75x+35≥7(11x+9)+4     Given

75x+35≥77x+63+4      Distributive Property

75x+35≥77x+67         Combine like terms

−2x+35≥67                 Subtraction Property of Order

−2x≥32                       Subtraction Property of Order

x≤−16                          Division Property of Order

Please give brainliest!

4 0
3 years ago
Read 2 more answers
If B = 3m - 5m2 +10 and A = -3 – m, find an expression that equals<br> 2B + 3 A in standard form.
Mashutka [201]
-5m2+5m+1 is the correct answer
6 0
2 years ago
Read 2 more answers
The covered part of this figure is a semicircle. What is the best approximation for the area of this figure?
zalisa [80]

Answer:

 94.18                            

Step-by-step explanation:

Given in the question a semi circle and a right angle triangle

Step 1

Find the diameter of the semi circle

To find the diameter we will use pythagorus theorem

<h3>hypotenuse² = height² + base²</h3>

here,

hypotenuse will be diameter of semicircle

height = 9

base = 4

Plug values in the formula above

diameter = √(9²+4²)

diameter = √97

Step 2

Find radius

<h3>radius = diameter / 2</h3>

Step 3

Area

<h3>π(r)²</h3>

π(√97/2)²

= 76.18

Step 4

Total surface area = area of circle + area of right angle triangle

                               = 76.18 + 1/2(9)(4)

                               = 94.18

6 0
2 years ago
what is the general form of the equation of a circle with its Center at -2 1 and passing through -4 one​
blondinia [14]

Answer:

\large\boxed{x^2+y^2+4x-2y+1=0}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

The general form of an equation of a circle:

x^2+y^2+Dx+Ey+F=0

We have the center (-2, 1). Substitute to the equation in the standard form:

(x-(-2))^2+(y-1)^2=r^2\\\\(x+2)^2+(y-1)^2=r^2

Put thr coordinates of the point (-4, 1) to the equation and calculate a radius:

(-4+2)^2+(1-1)^2=r^2\\\\r^2=(-2)^2+0^2\\\\r^2=4

Therefore we have the equation:

(x+2)^2+(y-1)^2=4

Convert to the general form.

Use (a\pm b)^2=a^2\pm 2ab+b^2

(x+2)^2+(y-1)^2=4\\\\x^2+2(x)(2)+2^2+y^2-2(y)(1)+1^2=4\\\\x^2+4x+4+y^2-2y+1=4\qquad\text{subtract 4 from both sides}\\\\x^2+y^2+4x-2y+1=0

5 0
3 years ago
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