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4 years ago

The importancê òf measurement

1 answer:

7 0

Measurements in physics is important because it enables people to argue using mathematics where numbers can be used to represent knowledge in a convenient manner when we show and communicate about a phenomenon.

Explanation:

When a physician is able to measure a phenomenon, then we get a foundation of understanding a lot of things in our universe.Measuring these things will help know how to use them in various applications.

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Measurements : brainly.com/question/12806328

Keywords : measurements

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Salt Flats of Utah, had a mass of 4100 kg, and its engine

Andrej [43]

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

f is the force

m is the mass

From the question we have

$a = \frac{68000}{4100} = \frac{680}{41} \\ = 16.58536$

We have the final answer as

Hope this helps you

8 0

3 years ago

Explain which planets have seasons and why some planets have none at all.

Sergeu [11.5K]

Answer:

Some planets have seasons some don't bc of the distance from the sun some of them are too cold or too hot to have seasons

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3 years ago

A 1.6 kg block slides with a speed of .95 m/s on a frictionless, horizontal surface until it encounters a spring with a spring c

Bas_tet [7]

Answer:

(a) the compression of the spring when the block comes to rest is 4cm

(b) speed of the block is 0.427 m/s

Explanation:

Given;

mass of the block, m = 1.6 kg

spring constant, k = 902 N/m

initial speed of the block, v₀ = 0.95 m/s

(a) the compression of the spring when the block comes to rest

when the block comes to rest, the final speed, vf = 0

Apply the law of conservation of energy;

¹/₂kx² = ¹/₂mv₀²

kx² = mv₀²

$x = \sqrt{\frac{mv_0^2}{k} } \\\\x = \sqrt{\frac{1.6(0.95)^2}{902} }\\\\x = 0.040 \ m$

x = 4 cm

(b) speed of the block

Apply the law of conservation of energy;

¹/₂mv² = ¹/₂kx²

mv² = kx²

$v = \sqrt{\frac{kx^2}{m}}\\\\v = \sqrt{\frac{(902)(0.018)^2}{1.6}}\\\\v = 0.427 \ m/s$

7 0

3 years ago

Glucose typically enters the cell through which mechanisms

Viktor [21]

Answer:

facilitated diffusion

3 0

3 years ago

A 5kg cat is lifted 2m into the air. How much GPE does it gain

luda_lava [24]

m = mass of the cat being lifted = 5 kg

h = height to which the cat is raised into air = 2 m

g = acceleration due to gravity of earth = 9.8 m/s²

U = gravitational potential energy gained by the cat

Gravitational potential energy gained by the cat is given as

U = m g h

inserting the values in the above equation

U = (5 kg) (9.8 m/s²) (2 m)

U = (5 x 9.8 x 2) (kg m²/s²)

U = 98 J

5 0

4 years ago

The importancê òf measurement​

The importancê òf measurement