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zhuklara [117]
3 years ago
11

Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te

mperatura y presión constantes, de manera que el volumen final es el doble del volumen inicial. Calcular la cantidad de N2(g) en el recipiente, expresada en moles.
Chemistry
1 answer:
notsponge [240]3 years ago
4 0

Answer:

high schools community of college students who is looking my friend you my friend and maddie intro high college football of community College program maddie I work peen and caty high schools community College program g2

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Do you think that all foods containing carbohydrates are healthful? Explain plz:(
deff fn [24]

Answer:

Yes

Explanation:

because some foods have carbohydrates but are healthy

8 0
3 years ago
Your teacher asks you to design an experiment that shows how plants respond to changes in their environment. You have two identi
tia_tia [17]

Answer:

1.  Make observations.

Determine whether the plant grown under the white light bulb or the plant grown under the red light bulb grew better.

Observations are anything we notice which lead to a question in our mind.

2. Ask a question.

Do plants grow as well under a different color of light?

As this is a question being asked, hence it will be the question for the scientific method of research.

3. Test the hypothesis.

Put one plant under a white light bulb, and  place the other plant under a red light bulb.  Measure the growth of the two plants.

To test the hypothesis, experiments are performed. This is the experiment.

4. Analyze the results, and make a conclusion.

Plants grow well under sunlight or a light bulb  with a hot, white light.

After the experiments, the results are compiled and a conclusion is drawn.

5. Test or modify.

If you observe no change, repeat the experiment with different colors of light bulbs. If there is a change, repeat the experiment for one or two more trials to ensure that the color of the light bulb contributes to the change.

If our hypothesis does not come out to be true, then another hypothesis can be generated and tests be done for it.

6 0
3 years ago
Read 2 more answers
He isotope 62(over28ni has the largest binding energy per nucleon of any isotope. calculate this value from the atomic mass of n
irina [24]
The atomic mass of the isotope Ni ( 62 over 28 ) = 61.928345 amu.
Mass of the electrons: 28 · 5.4584 · 10^(-4 ) amu = 0.0152838 amu ( g/mol )
Mass of the nuclei:
61.928345 amu - 0.0152838 amu = 61.913062 amu (g/mol)
The mass difference between a nucleus and its constituent nucleons is called the mass defect.
For Ni ( 62 over 28 ): Mass of the protons: 28 · 1.00728 amu = 28.20384 amu
Mass of the neutrons: 34 · 1.00866 amu = 34.299444 amu
In total : 62.49828 amu
The mass defect = 62.49828 - 61.913062 = 0.585218 amu
Nucleus binding energy:
E = Δm · c² ( the Einstein relationship )
E = 0.585218 · ( 2.9979 · 10^8 m/s )² · 1 / (6.022 · 10^23) · 1 kg / 1000 g =
= 0.585218 · 8.9874044 · 10 ^16 : (6.022 · 10^23) · 0.001 =
= ( 5.2595908 : 6.022 ) · 0.001 · 10^(-7 ) =
= 0.0008733 · 10^(-7) J = 8.733 · 10^(-11) J
The nucleus binding energy per nucleon:
8.733 · 10^(-11) J : 62 =  0.14085 · 10 ^(-11) =
= 1.4085 · 10^(-12) J per nucleon.
4 0
3 years ago
My cat, Copper, is a picky eater. I've noticed that he eats better when the TV is on. To
jok3333 [9.3K]
I was going to help but I don’t understand the question
8 0
3 years ago
The Bay of Fundy in Nova Scotia, Canada is reported to have the largest tides in the world with high tide and low tide occurring
topjm [15]

The rate in m/s is 5.2 * 10^-4 m/s.

<h3>What is the rate in m/s?</h3>

We know that the speed is given as the ratio of the distance covered to the time taken. In this case, we have been told that the rate at which the tide rises is 6.08 ft per hour. We would now need to convert the rate from  6.08 ft per hour to m/s.

Now;

We know that;

1 foot/hour = 8.5 * 10^-5 m/s

6.08 ft per hour = 6.08 ft per hour * 8.5 * 10^-5 m/s/1 foot/hour

= 5.2 * 10^-4 m/s

Learn more about speed:brainly.com/question/28224010

#SPJ1

3 0
2 years ago
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