Answer: the upper right portion of the periodic table.
Explanation:
Answer:
2.50 atm
Explanation:
We have 10.4 g of DDT (solute), whose molar mass is 354.50 g/mol. The corresponding moles are:
10.4 g × (1 mol/354.50 g) = 0.0293 mol
The molarity of the solution is:
M = moles of solute / liters of solution
M = 0.0293 mol / 0.286 L
M = 0.102 M
We can find the osmotic pressure (π) using the following pressure.
π = M × R × T
where,
R: ideal gas constant
T: absolute temperature
π = M × R × T
π = 0.102 M × 0.0821 atm.L/mol.K × 298 K
π = 2.50 atm
Answer:
Average rate of reaction is 0.000565 M/min
Explanation:
Applying law of mass action for the given reaction:
Average rate = ![-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO_{2}]}{\Delta t}=\frac{\Delta [O_{2}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5CDelta%20%5BNO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B%5CDelta%20%5BO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
Where, ![-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of disappearance of 
, ![\frac{1}{4}\frac{[NO_{2}]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%5Cfrac%7B%5BNO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of appearance of 
and ![\frac{[O_{2}]}{\Delta t}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BO_%7B2%7D%5D%7D%7B%5CDelta%20t%7D)
represents average rate of appearance of 
Here,![-\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=-%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
= 
So average rate of reaction = ![[tex]-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}](https://tex.z-dn.net/?f=%5Btex%5D-%5Cfrac%7B1%7D%7B2%7D%5Cfrac%7B%5BN_%7B2%7DO_%7B5%7D%5D%7D%7B%5CDelta%20t%7D)
[/tex] = 
