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vodka [1.7K]
3 years ago
11

A bus increases iys velocity from 20m/s to 30m/s in 2 seconds. Find ots acceleration​

Physics
2 answers:
Katyanochek1 [597]3 years ago
4 0

Answer:

5ms^-2 be the acceleration

Vinvika [58]3 years ago
4 0

Explanation:

Solution,

Given,

u=20m/s

v=30m/s

t=2 seconds

Now,

According to the formula of acceleration,we have

a=v-u/t

=30-20/2

=10/2

=5m/s^2

So, it's acceleration is 5m/s^2

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NeX [460]
Just explain the day of how you were shopping and there you have it
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3 years ago
A 55 kilogram person jumps off a cliff and hits the water 5.8 seconds later, how high is the cliff above the water?
ElenaW [278]
R=ut+gt^2/2
r- displacement (height to find)
u - initial speed (zero)
t - time taken

r=0*5.8 + 10*5.8^2 /2 = 168.2 meters
8 0
3 years ago
boris the bear is lumbering along at a constant rate of 4.0 m/s. if he walks for 600.0 seconds, how far will he travel?​
irina1246 [14]

Answer: 2400m

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6 0
3 years ago
If earth increase the distance from the sun, what will happen to the period of orbi t(the time it takes to complete one revoluti
Mandarinka [93]

The period of the orbit would increase as well

Explanation:

We can answer this question by applying Kepler's third law, which states that:

"The square of the orbital period of a planet around the Sun is proportional to the cube of the semi-major axis of its orbit"

Mathematically,

\frac{T^2}{a^3}=const.

Where

T is the orbital period

a is the semi-major axis of the orbit

In this problem, the question asks what happens if the distance of the Earth from the Sun increases. Increasing this distance means increasing the semi-major axis of the orbit, a: but as we saw from the previous equation, the orbital period of the Earth is proportional to a, therefore as a increases, T increases as well.

Therefore, the period of the orbit would increase.

Learn more about Kepler's third law:

brainly.com/question/11168300

#LearnwithBrainly

5 0
3 years ago
A high-jumper clears the bar and has a downward velocity of - 5.00 m/s just before landing on an air mattress and bouncing up at
Jobisdone [24]

-- As she lands on the air mattress, her momentum is (m v)

Momentum = (60 kg) (5 m/s down) = 300 kg-m/s down

-- As she leaves it after the bounce,

Momentum = (60 kg) (1 m/s up) = 60 kg-m/s up

-- The impulse (change in momentum) is

Change = (60 kg-m/s up) - (300 kg-m/s down)

Magnitude of the change = <em>360 km-m/s </em>

The direction of the change is <em>up /\ </em>.

8 0
3 years ago
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