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4 years ago

A hummingbird flies forward and backward. Its motion is shown on the above graph of horizontal Position and

Physics

1 answer:

harina [27]4 years ago

8 0

Answer:

The hummingbird travels the total distance is 10 m

Explanation:

Given that,

A hummingbird flies forward and backward.

According to figure,

We know that,

The total distance is equal to the sum of all distance.

Forward direction is positive and backward direction is negative.

We need to calculate the hummingbird travels the total distance

Using figure,

$D=d_{1}+d_{2}+d_{3}+d_{4}$

Put the value into the formula

$D=6+(-4)+2+6$

$D=10\ m$

Hence, The hummingbird travels the total distance is 10 m.

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Tom and Mary are riding a merry-go-round. Tom is on a horse about half way between the center and the outer rim, and Mary is on

iren2701 [21]

Answer:

Explanation:

Given

Tom is on half way between the center and the outer rim

Mary is on the extreme outer rim

Suppose $\omega$ is the angular velocity of ride with radius of outer rim be R

$\alpha =$ angular acceleration of Ride

At any instant both Tom and Mary experience the same angular speed

(b)Linear velocity at any instant

$v_{Tom}=\omega \times R$

$v_{Mary}=\omeag \times \frac{R}{2}$

Thus Tom has higher linear speed

$a_r=\omega ^2\times r$

$a_{Tom}=\omega ^2\times R$

$a_{Mary}=\omega ^2\times \frac{R}{2}$

Tom has higher radial Acceleration as it is directly Proportional of radius

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3 years ago

Earth orbits once around the Sun about every 365 days. The Moon orbits around Earth. About how many days does it take the Moon t

PtichkaEL [24]

The answer is is 730.5 days rounded, so A. 730

3 0

4 years ago

g If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?

kiruha [24]

Answer:

Range will become 4 times of initial range

Explanation:

Let the velocity of projection is u

And angle at which projectile is projected is $\Theta$

And acceleration due to gravity is $g\ m/sec^2$

So range of projectile is equal to $R=\frac{u^2sin2\Theta }{g}$ ........eqn 1

Now in second case it is given that velocity of launching is doubled

So new velocity $u_{new}=2u$

So new range will be equal to $R_{new}=\frac{(2u)^2sin2\Theta }{g}=\frac{4u^2sin2\Theta }{g}$ .....eqn 2

Now dividing eqn 2 by eqn 1

$\frac{R_{new}}{R}=\frac{4u^2sin2\Theta }{g}\times \frac{g}{u^2sin2\Theta }$

$R_{new}=4R$

So if we double the initial launch speed then range will become 4 times

4 0

4 years ago

A 2 kg object is traveling in a circular path. What is the centripetal acceleration and centripetal force if the radius of the p

Ilya [14]

Answer:

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F = mv²/R = 2(16.7) = 33.3 N

Explanation:

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3 years ago

What is mechanics physics

nignag [31]

Mechanics Physics is a area in physics dealing with motion of objects talking about when force applied to objects what happens whether displacement or changes of the position

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3 years ago