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Sholpan [36]
4 years ago
7

Which method to determine the age of artifacts measures the rate of decay in atoms?

Physics
1 answer:
Korolek [52]4 years ago
3 0
Answer: Kalium Argon dating

Kalium or Potassium radioactive atom that commonly found in stone or artifact. Since Kalium is radioactive, it will be reduced and converted into another atom(in this case argon) after a set of time. You can determine the time elapsed by comparing the Kalium with argon mass.
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A pulley ,it the same concept is used to raise an elevator
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A force platform is a tool used to analyze the performance of athletes measuring the vertical force that the athlete exerts on t
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Answer:

a.I=981.34 N*s

b.v_f=3.96 m/s

c.v_{f1}=3.63m/s

d.y_f=0.673m

Explanation:

Given: m=67kg, h=0.720m, 0

a.

I=\int\limits^{t_1}_{t_2} {F(t)} \, dt

F(t)=9200*t-11500t^2

I=\int\limits^{0.8s}_{0s}{9200*t-11500*t^2} \, dt

I=4600*t^2-3833.3*t^3|(0.80,0)

I=2944-1962.66=981.35

I=981.34 N*s

b.

v_f^2=v_i^2+a*y'

Starting from the rest

v_f^2=0+2*9.8m/s^2*0.80s

v_f^2=15.68

v_f=\sqrt{15.68m^2/s^2}=3.96 m/s

c.

I_{total}=p_f

I_1-m*g*d=m*v_{f1}-m*v_f

981.34-67kg*9.8m/s^2*0.720=67.0kg*v_{f1}-67.0kg*(-3.96m/s)

Solve to vf

v_{f1}=3.63m/s

d.

v_f^2=v_i^2+2*a*y_f'

y_f'=v_i/2*a =(3.63m/s)^2/2*9.8m/s^2

y_f=0.673m

7 0
3 years ago
Bowl of water A bowl full of water is sitting out in a pouring rainstorm. Its surface area is 500 cm2. The rain is coming straig
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Answer: 4.9 x 10-3 N

Explanation:

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V = 5 m/s

R = 10^-3 g/cm^2.sec = 10^-2kg/m^2 . sec

Prain water = R / V = 10^-2 / 5 = 2 x 10-3 kg/m^3

For the stationary bowl,

dm/dt =pAv= RA

F= dp/dt = (dm/dt) v = RAv = 2.5 x 10^-3 N

Bowl moving upwards to speed u = 2 m/s

dm/dt = pA ( v + u) / v

F = dp/dt = (dm/dt)(v+u) = RA (v+u)^2 / v = 4.9 x 10^-3 N

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Please help! The image produced by a concave mirror is ? .
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Answer:

is a reflection.

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Explanation:

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They are called <span>Frequency-modulated</span>
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