Balanced equation:
Ca(OH)2+H2SO4=CaSO4+2 H20<span />
Answer: The name of given molecule is
3-Methylpent-2-ene.
Explanation: First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or
Pent-2-ene2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or
3-Methylpent-2-ene
From what I experienced I gets really loud with the smell but other than that nothing happens just the smell gets stronger
The answer would be gold because gold is having a property of malleable
so it can be drawn into thin sheets
The value of pka for
in an aqueous solution is 9.2.
<h3>What is Kb?</h3>
Kb denotes the base dissociation constant.
pKa + pKb =14 at 25 degree celcius.
pKa + 4.8 =14
pKa = 9.2
pKb is the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.
It is used to determine the strength of a base or alkaline solution.
The value of pka for
in an aqueous solution is 9.2.
Learn more about pka here:
brainly.com/question/14124805
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