Answer is: mass of product is 649.35 g.
Balanced chemical reaction: Ca(s)+Cl₂<span>(g) → CaCl</span>₂<span>(s).
m(Ca) = 23.4 g.
n</span>(Ca) = m(Ca) ÷ M(Ca).
n(Ca) = 23.4 g ÷ 40 g/mol.
n(Ca) = 0.585 mol.
From chemical reaction: n(Ca) : n(CaCl₂) = 1 : 1.
n(CaCl₂) = 0.585 mol.
m(CaCl₂) = 0.585 mol · 111 g/mol.
m(CaCl₂) = 649.35 g.
Answer:
0.075 M
Explanation:
5Fe²⁺(aq) + MnO₄⁻(aq) + 8H⁺(aq) → 5Fe³⁺(aq) + Mn²⁺(aq) + 4H₂O(ℓ)
Using the moles of Fe²⁺ that reacted, we can <em>calculate the reacting moles of MnO₄⁻</em>:
0.0450 mol Fe⁺² * = 0.0090 mol MnO₄⁻
Now we divide the moles of MnO₄⁻ by the volume in order to <u>calculate the molarity of the solution</u>, keeping in mind that 120.0 mL = 0.120 L.
0.0090 mol MnO₄⁻ / 0.120 L = 0.075 M
Answer:
713.33 g/mol
Explanation:
The<em> freezing-point depression equation</em> is:
Where ΔT is the difference in temperature. The freezing point of pure benzonitrile is -12.75 °C, so ΔT = -12.75 - (-13.8) = 1.05 °C
Kf is the cryopscopic constant, which is 5.35 °C/m (as reported by the CRC Handbook).
m is the molality (moles compound X/kg benzonitrile).
So first we <u>calculate the molality</u>:
Now we <u>calculate the moles of X that were added</u>:
75 g ⇒ 75/1000 = 0.075 kg
- 0.196 m = mol X / 0.075 kg
Finally we <u>calculate the molar mass of X</u>, using the added mass:
- 10.5 g / 0.0147 mol = 713.33 g/mol
Answer:
Subject of the experiment and out of scope
Explanation:
In any research study, the process of thing studied is basically the subject of the experiment on which research is conducted to determine the outcomes. If any thing lies out of the experimental process reach, then it is said to be out of scope of the experiment.
Woah I’m that’s a bit too long