0.08 / 0.5216
Answer: 0.15337423312
If you look at the numbers past the decimal point, the first digit - 8 - is in the tenths place. So, - 7 - is in the hundredths. What number is beside that? 4. When you round four, does it go up to ten or down to zero? Which is it closer to? The answer is zero.
So, the 7 in the hundredths place stays the same and any numbers after it are turned to zeros and cut off. Ending up with 26,379.87
The answer is 3/7 (Three over seven). You ADD the number of total possibilities (animal characters + human characters = 7 total characters) for the denominator and put in the number (or section) you're looking at as the numerator
There seems to be a typo. You wrote 1313, but I'm assuming you meant to say the fraction 1/3. If this assumption is correct, then continue with the rest of the solution. If the assumption is not correct, then ignore what I wrote below and please provide clarification of what the "1313" should represent. Thank you.
----------------
B = your brother's age
S = your sister's age
Y = your age
All of these ages are current present day ages.
---------------
"your brother is 1/3 your age" so B = (1/3)Y or B = Y/3.
"Your sister is 6 years older than your brother" so S = B+6
"Your sister is 10 years old" so S = 10.
---------------
S = B+6
B+6 = S
B+6 = 10 ... plug in S = 10
B+6-6 = 10-6 ... subtract 6 from both sides
B = 4
Your brother is 4 years old.
---------------
B = Y/3
Y/3 = B
Y/3 = 4 .... plug in B = 4
3(Y/3) = 3*4 ... multiply both sides by 3
Y = 12
<h3>Answer: Your age is 12 years old.</h3>
note: This answer hinges on assumption that the "1313" should be "1/3".
(1)
Mean length of all fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)
= 62/10
=<em> 6.2</em>
(2)
Mean length of adult fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (12 + 5 + 8 + 10)/(4)
= 35/4
=<em> 8.75</em>
(3)
Mean length of juvenile fish in the sample - 
<u>Mean</u> = (Sum of observations)/(Number of observations)
= (5 + 3 + 2 + 9 + 4 + 4)/(6)
= 27/6
<em>= 4.5</em>
(4)
Percentage of sample that were adult fish - 
<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100
% = (4/10) × 100
<em>% = 40</em>
(5)
Percentage of sample that were juvenile fish - 
<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100
% = (6/10) × 100
<em>% = </em><em>6</em><em>0</em>
(6)
Percentage of sample that were juveniles over 8 inches long - 
<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100
% = (1/10) × 100
<em>% = </em><em>1</em><em>0</em>
