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3 years ago

At what point will f(x) = 3^x exceed g(x) = 2x + 5 and h(x) = x^2 +4?

Mathematics

1 answer:

Alex73 [517]3 years ago

5 0

Answer: B ( 2,9) .

Step-by-step explanation:

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which expression DOES NOT represent a square root of a perfect square integer? A) 100 B) 64 C) 81 D) 89

Ipatiy [6.2K]

Its 89 because 9 times 2 is 81 and 10 times 2 is 100 there nothing to multiple 2 by something to get 89

4 0

3 years ago

Read 2 more answers

What is the common ratio of the sequence? -2,6,-18,54

aivan3 [116]

ANSWER

The common ratio is -3.

EXPLANATION

In general, the common ratio of a Geometric Sequence is given by:

$r = \frac{a_{n+1}}{a_{n}}$

We can find the common ratio using any two consecutive terms of the geometric sequence by dividing the subsequent term by the previous term.

The given sequence is -2,6,-18,54

Using the first two terms the common ratio is

$r = \frac{6}{ - 2} = - 3$

We could also used the second and third terms to get

$r = \frac{ - 18}{6} = - 3$

and so on and so forth.

Therefore the common ratio is -3.

6 0

3 years ago

What is the solution for x in the glven equation? V9x + 7+ 12x = 7

Oliga [24]

Answer:

C. x = 2

Step-by-step explanation:

3 0

3 years ago

Which expression is equivalent to 4 square root 6 divided by 3 root 2

denis-greek [22]

Answer:

The expression is equivalent to 4 square root 6 divided by 3 root 2 is:

8/3

Step-by-step explanation:

Given expression:

4 square root 6 divided by 3 root 2

$\frac{4\sqrt{6}}{3\sqrt{2} }$

$=\frac{4\sqrt{2*2*2}}{3\sqrt{2} }$

$=\frac{4\sqrt{2*2^{2} }}{3\sqrt{2} }$

square root of 2² = 2 hence,

$=\frac{4*2\sqrt{2}}{3\sqrt{2} }$

$=\frac{8\sqrt{2}}{3\sqrt{2} }$

Common terms in the numerator and denominator cancels each other out

$=\frac{8}{3}$

By solving the expression using simple mathematical rules, we got an equivalent expression of

$\frac{4\sqrt{6}}{3\sqrt{2} } = \frac{8}{3}$

7 0

3 years ago

Read 2 more answers

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote R as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

6 0

3 years ago