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jarptica [38.1K]

2 years ago

14

A california condor is sitting on the top branch of a redwood tree and has a GPE of 12,100 J. If the condor has a mass of 8kg, w

hat is the height of the branch the condor is perched on? what would this height be in feet?

1 answer:

DanielleElmas [232]2 years ago

3 0

Answer:

william h. seward secured the purchase of alaska from:

Explanation:

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An object falls a distance h from rest. If it travels 0.460h in the last 1.00 s, find (a) the time and (b) the height of its fal

nadya68 [22]

Answer:

A. Time, t = 4.35s

B. Height of its fall, S = 92.72m

Explanation:

Vo = 0 m/s

Vi = 0.46h m/s

S = h m

a = 9.81 m/s2

To calculate the time taken, we need to get the value of the distance, h.

Using the equations of motion,

Vi^2 = Vo^2 + 2aS

Where Vi = final velocity

Vo = initial velocity

a = acceleration due to gravity

S = height of its fall

(0.46h)^2 = 0 + 2*9.81*h

0.2116h^2 = 19.62h

h = 19.62/0.1648

= 92.722 m

To calculate the time,

S = Vo*t +(1/2)*a*t^2

92.772 = 0 + (1/2)*9.81*t^2

t^2 = 185.44/9.81

= 18.904

t = sqrt(18.904)

= 4.348 s

7 0

3 years ago

Read 2 more answers

Reeti has a mass of 51.0 kg. The Gravitron, a ride that spins so fast that the floor can be removed without the riders falling,

Serggg [28]

Answer:

L = 2774.4 $kgm^{2}/s$

Explanation:

Using the formula

L = mvr

Where L is angular momentum

m is mass

v is velocity

r is radius

m= 51kg , v=17m/s , r=3.2m

L = 51×17×3.2

L = 2774.4 $kgm^{2}/s$

7 0

2 years ago

1. What do you think determines the type of traits you inherit?

Ainat [17]

Answer: How dominant one persons genes are.

Explanation:

The more dominant a trait is, the more likely someone will inherit them.

6 0

3 years ago

An object is held 24.8 cm from a lens of focal length 16.0 cm. What is the magnification of the image?

Gwar [14]

Answer: 1.8

Explanation:

You are given

the object distance U = 24.8 cm

Focal length F = 16.0 cm

First find the image distance by using the formula:

1/f = 1/u + 1/v

Where V = image distance

Substitute u and f into the formula

1/16 = 1/24.8 + 1/v

1/ v = 1/16 - 1/24.8

1/v = 0.0625 - 0.04032258

1/v = 0.022177

Reciprocate both sides by dividing both sides by one

V = 45.09 cm

Magnification M is the ratio of image distance to the object distance. That is,

M = V/U

Substitute V and U into the formula

M = 45.09/24.8

M = 1.818

Magnification of the image is therefore equal to 1.8 approximately

3 0

3 years ago

A yoyo with a mass of m = 150 g is released from rest as shown in the figure.

avanturin [10]

(1) The linear acceleration of the yoyo is 3.21 m/s².

(2) The angular acceleration of the yoyo is 80.25 rad/s²

(3) The weight of the yoyo is 1.47 N

(4) The tension in the rope is 1.47 N.

(5) The angular speed of the yoyo is 71.385 rad/s.

<h3> Linear acceleration of the yoyo</h3>

The linear acceleration of the yoyo is calculated by applying the principle of conservation of angular momentum.

∑τ = Iα

rT - Rf = Iα

where;

I is moment of inertia
α is angular acceleration
T is tension in the rope
r is inner radius
R is outer radius
f is frictional force

rT - Rf = Iα ----- (1)

T - f = Ma -------- (2)

a = Rα

where;

a is the linear acceleration of the yoyo

Torque equation for frictional force;

$f = (\frac{r}{R} T) - (\frac{I}{R^2} )a$

solve (1) and (2)

$a = \frac{TR(R - r)}{I + MR^2}$

since the yoyo is pulled in vertical direction, T = mg $a = \frac{mgR(R - r)}{I + MR^2} \\\\a = \frac{(0.15\times 9.8 \times 0.04)(0.04 - 0.0214)}{1.01 \times 10^{-4} \ + \ (0.15 \times 0.04^2)} \\\\a = 3.21 \ m/s^2$

<h3>Angular acceleration of the yoyo</h3>

α = a/R

α = 3.21/0.04

α = 80.25 rad/s²

<h3>Weight of the yoyo</h3>

W = mg

W = 0.15 x 9.8 = 1.47 N

<h3>Tension in the rope </h3>

T = mg = 1.47 N

<h3>Angular speed of the yoyo </h3>

v² = u² + 2as

v² = 0 + 2(3.21)(1.27)

v² = 8.1534

v = √8.1534

v = 2.855 m/s

ω = v/R

ω = 2.855/0.04

ω = 71.385 rad/s

Learn more about angular speed here: brainly.com/question/6860269

#SPJ1

3 0

1 year ago