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3 years ago

The ruminant stomach has four compartments including the rumen, reticulum, omasum and large intestine,

Physics

1 answer:

Ipatiy [6.2K]3 years ago

5 0

Answer:

<h2><u>False</u></h2>

<u><em>It has four compartments just not including all of those</em></u>

Explanation:

Ruminant stomachs have four compartments: the rumen, the reticulum, the omasum and the abomasum.

Anatomy of the ruminant digestive system includes the mouth, tongue, salivary glands (producing saliva for buffering rumen pH), esophagus, four-compartment stomach (rumen, reticulum, omasum, and abomasum), pancreas, gall bladder, small intestine (duodenum, jejunum, and ileum), and large intestine (cecum, colon, and rectum).

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In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is

meriva

The spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

<h3>What is double slit experiment?</h3>

The double-slit experiment serves as a proof in current physics that both light and matter may exhibit properties of classically defined waves and particles. It also illustrates the inherently probabilistic nature of quantum mechanical events. Thomas Young carried out the first experiment of this kind employing light in 1802, illustrating how light behaves like a wave. It was formerly believed that light was made up of either waves or particles. About a century later, with the advent of modern physics, it was discovered that light may in fact exhibit behaviour like that of both waves and particles. The identical behaviour of electrons was first shown by Davisson and Germer in 1927, and it was later extended to atoms and molecules.

The separation between the slits, d = 0.05mm = 5×10⁻⁵ m

The distance from the slits to a screen, D = 2.5 m

Let x is the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits,

λ = 600nm = 6× 10⁻⁷ m

We know that the bright fringe is given by :

y = nλD/d

So, the spacing between the first-order and second-order bright fringes is :

x = 2λD/d - λD/d

x = λD/d

x = 6 × 10⁻⁷ × 2.5/5 × 10⁻⁵

x = 0.03 m

x = 3 cm

So, the spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

to learn more about double slit experiment go to -

brainly.com/question/28108126

#SPJ4

8 0

1 year ago

Uranus and Neptune may have a compressed liquid water ocean beneath their atmospheres. What three pieces of evidence support thi

mart [117]

Answer:

Distance from sun, orbit and rotation. Presence of interior oceans, and elements that forms compressed water.

Explanation:

Both the planets are Jovian planets and have layers formed by ice such as that of Uranus does not have any surface. Such as the planet is only rotating fluids. While 80% of the mass of Neptune is made up of fluids or icy water and also consists of ammonia and methane.

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3 years ago

A gymnast of mass 70.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t

DiKsa [7]

Answer:

T = 686.7N

Explanation:

For this exercise we will use Newton's second law in this case there is no acceleration,

∑ F = ma

T -W = 0

The gymnast's weight is

W = mg

We clear and calculate the tension

T = mg

T = 70 9.81

T = 686.7N

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3 years ago

How can the shapes of a boat and an airplane affect how water and wind forces act on the objects?

gulaghasi [49]

It would be Aerodinmic

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4 years ago

In this week's experiment, you send an unpolarized light beam through two polarizers in series. You orient the first polarizer s

g100num [7]

Answer:

Part a)

$\theta = 90 degree$

so the polarization axis of two polarizers must be at 90 degree

Part b)

$\theta = 20 + 14.3 = 34.3 degree$

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

Explanation:

Part 1)

As per law of Malus we know that the intensity of light coming from the second polarizer and the intensity of the light from first polarizer is related as

$I = I_o cos^2\theta$

now we know that we rotate the second polarizer till the intensity of the light becomes zero

so we will have

$I = 0$

so we will have

$\theta = 90 degree$

so the polarization axis of two polarizers must be at 90 degree

Part b)

when two axis are inclined at 90 degree then scale reads 104.3 degree

so here the scale exceeds the reading by

$\Delta \theta = 104.3 - 90 = 14.3$

so in order to make them inclined at 20 degree we will have

$\theta = 20 + 14.3 = 34.3 degree$

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

7 0

4 years ago