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charle [14.2K]
3 years ago
8

A small amount wet of hydrogen gas can be prepared by the reaction of zinc with excess hydrochloric acid and trapping the gas pr

oduced in an inverted tube initially filled with water. If the total pressure of the gas in the collection tube is 729.7 mmHg at 25 C, what is the partial pressure of the hydrogen
Chemistry
1 answer:
dybincka [34]3 years ago
4 0

Answer : The partial pressure of the hydrogen is, 705.9 mmHg

Explanation :

According to the Dalton's law of partial pressure,

P_T=P_{H_2}+P_{H_2O}

where,

P_T = total pressure of the gas = 729.7 mmHg

P_{H_2} = partial pressure of the hydrogen gas = ?

P_{H_2O} = partial pressure of the water = 23.8 mmHg (standard value)

Now put all the given values in the above expression, we get:

729.7mmHg=P_{H_2}+23.8mmHg

P_{H_2}=705.9mmHg

Therefore, the partial pressure of the hydrogen is, 705.9 mmHg

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2 years ago
The protein lysozyme unfolds at a transition temperature of 75.5°C, and the standard enthalpy of transition is 509 kJ mol-1. Cal
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Answer:

0.4774 KJ/K.mol

Explanation:

We are told that the transition at 25.0°C occurs in three steps. Steps i, ii and iii.

Thus;

the entropy of unfolding of lysozyme = ΔS_i + ΔS_ii + ΔS_iii

Now,

C_p,m(unfolded protein) = C_p,m(folded protein) + 6.28 kJ/K.mol

Now, for the first process, ΔS_i is given as;

ΔS_i = C_p,m × In(T2/T1)

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T1 = 25°C = 25 + 273.15K = 298.15 K

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Now, for the third process, ΔS_iii is given as;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(T1/T2)

Thus;

ΔS_iii = (C_p,m + 6.28 kJ/K.mol) × In(298.15/348.65)

Now, we don't know C_pm. So, we have to find a way to eliminate it. We will do it by rewriting In(298.15/348.65) in such a way that when ΔS_iii is added to ΔS_i, C_p,m will cancel out. Thus;

In(298.15/348.65) can also be written as;

In(348.65/298.15)^(-1) or

- In(348.65/298.15)

Thus;

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Now, let's add ΔS_iii to ΔS_i to get;

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] + [(-C_p,m - 6.28 kJ/K.mol) × In(348.65/298.15)]

ΔS_i + ΔS_iii = [C_p,m × In(348.65/298.15)] - [C_p,m × In(348.65/298.15)] - [6.28In(348.65/298.15)]

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