All categories

3 years ago

How many valence electrons should you use to draw a Lewis structure of ammonia (NH3)?

Chemistry

2 answers:

stealth61 [152]3 years ago

7 0

You should use 8 valence electrons to draw a Lewis structure of ammonia. b) 8

Mekhanik [1.2K]3 years ago

4 0

Hello there,

Your correct answer would be 8.<span> There are </span>8 valence electrons<span> available for the Lewis structure for NH</span>3<span>.

Hope this helps

~Hottwizzlers</span>

You might be interested in

Fghgfgfgfftftftft ttcc

Ganezh [65]

Answer:

ybbbbgbg

Explanation:

4 0

3 years ago

Read 2 more answers

What type of molecule is shown below

Kobotan [32]

Answer is: C alkane.

Name of this molecule is n-hexane.

Hexane is alkane (acyclic saturated hydrocarbon, carbon-carbon bonds are single) of six carbon atoms.

Carbon atoms in hexane have sp3 hybridization.

In sp3 hybridization hybridize one s-orbital and three p-orbitals of carbon atom.

Alkene has one double bond and alkyne has one triple bond.

4 0

3 years ago

At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L . What volume wo

Nostrana [21]

Taking into account the Charles's law, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.

<h3>Charles's Law</h3>

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, at a constant pressure.

Volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles's law is a law that says that the quotient that exists between the volume and the temperature will always have the same value:

V÷ T= k

Considering an initial state 1 and a final state 2, it is satisfied:

V1÷ T1= V2÷ T2

<h3>Volume at 65°C</h3>

In this case, you know:

V1= 22.4 L
T1= 0 C= 273 K
V2= ?
T2= 65 C= 338 K

Replacing in Charles's law:

22.4 L÷ 273 K= V2÷ 338 K

Solving:

(22.4 L÷ 273 K) ×338 K= V2

Finally, the same amount of gas at the same pressure and 65 ∘C would occupy a volume of 27.73 L.

Learn more about Charles's law:

brainly.com/question/4147359

#SPJ1

3 0

1 year ago

Three kilograms of steam is contained in a horizontal, frictionless piston and the cylinder is heated at a constant pressure of

lakkis [162]

Answer:

Final temperature: 659.8ºC

Expansion work: 3*75=225 kJ

Internal energy change: 275 kJ

Explanation:

First, considering both initial and final states, write the energy balance:

$U_{2}-U_{1}=Q-W$

Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:

$dw=Pdv$