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natita [175]
3 years ago
15

Find the value of x ​

Mathematics
2 answers:
Gwar [14]3 years ago
5 0

Answer:

hello

Step-by-step explanation:

4x+3x+2x=180⁰

9x=180⁰

x=20

hope it helps

have a nice day

Dafna11 [192]3 years ago
5 0

Answer:

x= 20

Step-by-step explanation:

4x+3x+2x=180

9x=180

x=180/9

so

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3 years ago
Give 1 pair of Vertical and 1 pair of Supplementary angles
mojhsa [17]

Solution:

Vertical angles are a pair of opposite angles formed by intersecting lines. re vertical angles. Vertical angles are always congruent.

These two angles (140° and 40°) are Supplementary Angles because they add up to 180°:

Notice that together they make a straight angle.

Hence,

From the image

The following pairs form vertical angles

\begin{gathered} \angle1=\angle3(vertical\text{ angles)} \\ \angle2=\angle4(vertical\text{ angles)} \\ \angle5=\angle7(vertical\text{ angles)} \\ \angle6=\angle6(vertical\text{ angles)} \end{gathered}

Hence,

One pair of the vertical angles is ∠1 and ∠3

Part B:

Two angles are said to be supplementary when they ad together to give 180°

Hence,

From the image,

The following pairs are supplementary angles

\begin{gathered} \angle5+\angle6=180^0(supplementary\text{ angles)} \\ \angle5+\angle8=180^0(supplementary\text{ angles)} \\ \angle7+\angle8=180^0(supplementary\text{ angles)} \\ \angle6+\angle7=180^0(supplementary\text{ angles)} \\ \angle1+\angle2=180^0(supplementary\text{ angles)} \\ \angle1+\angle4=180^0(supplementary\text{ angles)} \\ \angle2+\angle3=180^0(supplementary\text{ angles)} \\ \angle3+\angle4=180^0(supplementary\text{ angles)} \end{gathered}

Hence,

One pair of supplementary angles is ∠5 and ∠6

8 0
1 year ago
How do I solve -2x > 6
vodomira [7]
I’m not the best with words but first you would have to treat the greater sign as a = sign. So..
-2x =6
/ /
-2 -2
X = -3
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3 years ago
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Allisa [31]
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4 0
3 years ago
Which statements are always true regarding the diagram? Select three options.
Maurinko [17]
Find : Which statements are always true regarding the triangle
m∠5 + m∠3 = m∠1
m∠3 + m∠4 + m∠5 = 180°
m∠5 + m∠6 =180°
m∠2 + m∠3 = m∠6
m∠2 + m∠3 + m∠5 = 180°
Solution:
External angle of triangle = Sum of opposite interior angles
m∠1 = m ∠3 + m∠5
m∠4 = m ∠2 + m∠5
m∠6 = m ∠2 + m∠3
4 0
3 years ago
Read 2 more answers
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