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3 years ago

If a car is traveling at a speed of 45 miles per hour, how farcan it travel in 40 minutes?

Physics

2 answers:

Nezavi [6.7K]3 years ago

5 0

45 divided my 60. Then multiple my 40 you get 30 miles

dusya [7]3 years ago

3 0

Answer:

30 miles

Explanation:

Step 1:

Divide -> 45/60= .75 miles/minute

Step 2:

Multiply -> .75 x 40= 30

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PE=?, m=.6kg, g=10m/s2, h=35m PLS HELP I NEED THIS DONE

Karo-lina-s [1.5K]

210J

PE is mgh in this context.

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3 years ago

You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is

madreJ [45]

Answer:

Explanation:

Given

Diameter of Pulley=10.4 cm

mass of Pulley(m)=2.3 kg

mass of book $(m_0)=1.7 kg$

height(h)=1 m

time taken=0.64 s

$h=ut+frac{at^2}{2}$

$1=0+\frac{a(0.64)^2}{2}$

$a=4.88 m/s^2and [tex]a=\alpha r$

where $\alpha$ is angular acceleration of pulley

$4.88=\alpha \times 5.2\times 10^{-2}$

$\alpha =93.84 rad/s^2$

And Tension in Rope

$T=m(g-a)$

$T=1.7\times (9.8-4.88)$

T=8.364 N

and Tension will provide Torque

$T\times r=I\cdot \alpha$

$8.364\times 5.2\times 10^{-2}=I\times 93.84$

$I=0.463\times 10^{-2} kg-m^2$

$I_{original}=\frac{mr^2}{2}=0.31\times 10^{-2}kg-m^2$

Thus mass is uniformly distributed or some more towards periphery of Pulley

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3 years ago

Describe a perfect day

kvv77 [185]

Answer:

A bright and sunny day not worrying about work or school no family drama just a day you can relax and be yourself surrounded by the people you love.

hope this helps

have a good day :)

Explanation:

7 0

2 years ago

Read 2 more answers

A point charge q1q1 is held stationary at the origin. A second charge q2q2 is placed at point aa, and the electric potential ene

Yuri [45]

Explanation:

The given data is as follows.

$U_{a} = 5.4 \times 10^{-8} J$

$W_{/text{a to b}} = -1.9 \times 10^{-8} J$

Electric potential energy ( $U_{b}$ ) = ?

Formula to calculate electric potential energy is as follows.

$U_{b} = U_{a} - W_{/text{a to b}}$

= $5.4 \times 10^{-8} J - (-1.9 \times 10^{-8} J)$

= $7.3 \times 10^{-8} J$

Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is $7.3 \times 10^{-8} J$ .

6 0

3 years ago

How do i solve this?

kenny6666 [7]

Answer:

hmmm i dont know....

Explanation:

i just wanted free point. TANKS YOU SIR!!

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3 years ago

If a car is traveling at a speed of 45 miles per hour, how farcan it travel in 40 minutes?​

If a car is traveling at a speed of 45 miles per hour, how farcan it travel in 40 minutes?