An incomplete combustion happened in the combustion of a hydrocarbon where carbon monoxide is produced. It happens when there is not enough oxygen to combust the hydrocarbon. The opposite is the complete combustion where CO2 and H2O is formed.
23. The correct answer would be a (AlPO4 + H2O).
This is an example of a neutralization reaction (an acid and a base react to form water and a salt).
24. a, combination reaction. There are two reactants and one product.
[Hint: 1 m/s=2.237 mi/hr]
Write it out to get an understanding of how to convert.
1} 3.0x10^8m/s over 1.
(Don't forget to put your units as stated above)
2} Utilizing the hint given you want to cancel out the unit that is being converted. (Ex: m/s)
-> 3.0x10^8 m/s over 1
TIMES
2.237 mi/hr over 1 m/s
Now notice that the m/s is on top and on bottom now, if you've written it out. The numerator has something in common with the denominator and can now be canceled out. (Cross out the m/s NOT the digits JUST the units)
3} You have now narrowed it down to digits and the desired unit you want.
-> 3.0x10^8 over 1
TIMES
2.237 mi/hr over 1
Remember: multiply the numbers straight across the numerator to get a new total for the numerator. The same will go for the denominator. Once you have 1 fraction left, it basically becomes a math equation.
Num ■(3.0×10^8)(2.237)= 671100000
Den ■ (1)(1)= 1
4} 671100000(mi/hr)/1= 671100000 mi/hr
If you thought you were done you're wrong. You have to consider the significant figures or sig figs. Learn the rules to sig figs and you'll ace this part.
You're answer is going to be 3 sig figs. Therefore, your answer is:
6.71x10^8 mi/hr
Elements with three p-electrons....
That would be N, P, As, Sb, and Bi -- elements in group 15
For example, energy diagram showing "empty" orbitals up through the 3p.
.....3p __ __ __
3s __
.....2p __ __ __
2s __
1s __
Energy diagram of phosphorous showing three unpaired electrons in 3p-sublevel
.....3p ↑_ ↑_ ↑_
3s ↑↓
.....2p ↑↓ ↑↓ ↑↓
2s ↑↓
1s ↑↓
According to Hund's rule, the electrons singly occupy the p-orbitals, and all have the same spin.
