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Fofino [41]
3 years ago
8

Can anyone give me examples of control groups ?

Chemistry
1 answer:
alexgriva [62]3 years ago
7 0

Answer:

In an experiment in which blood pressure medication is tested, one group is given the blood pressure medication while the control group is given a placebo pill.

In a test of anxiety treatment, one group attends individual therapy sessions and receives a new medication. The control group receives only an inert pill.

A treatment for drug addiction is being tested. A group of meth addicts are given the treatment while the control group is given the placebo.

Researchers are testing the effectiveness of a drug intended to reduce symptoms of Crohn's disease. Many sufferers of Crohn's disease are recruited for the effort and the group that receives the placebo is the control group.

A treatment for hair loss in men is being tested. Men of the same age range are gathered. One group receives an application with the active ingredient while the control group receives an application that appears the same but does not have the active ingredient in it.

hope this helped you

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Acid rain is represented by the formula H2SO4. How many atoms of sulfur are present in one molecule of acid rain?
sergiy2304 [10]

Answer: A. one atom

Explanation: i did some research on it and that is what i found.

3 0
3 years ago
The isotope chromium-51 has a half-life of 28 days. if the original sample had a mass of 28.0 grams, what mass of the chromium-5
GalinKa [24]
Check the attached file for the answer.

5 0
4 years ago
When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
4 years ago
Solve the following equation:13x - 22 = 30​
Pavlova-9 [17]

Answer:

52/13

Explanation:

13X=30+22

x=52/13

7 0
3 years ago
Calculate the number of moles in 180 grams of Magnesium Chloride
BabaBlast [244]

Answer:

0.5 moles

Explanation:

u will get molar mass = 95.2 I think

then number of moles = molar mass÷ mass

=95.2÷180=0.5

3 0
3 years ago
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