What is the voltage in a circuit if the current is 6 Amps and resistance is 6 ohms

An electron is moving through a magnetic field whose magnitude is 9.21 × 10^-4 T. The electron experiences only a magnetic force

Marysya12 [62]

Answer:

$\theta=10.60^{\circ}$

Explanation:

Given that,

Magnetic field, $B=9.21\times 10^{-4}\ T$

Acceleration of the electron, $a=2.3\times 10^{14}\ m/s^2$

Speed of electron, $v=7.69\times 10^{6}\ m/s$

The force due to this acceleration is balanced by the magnetic force as :

$ma=qvB\ sin\theta$

$sin\theta=\dfrac{ma}{qvB}$

$sin\theta=\dfrac{9.1\times 10^{-31}\times 2.3\times 10^{14}}{1.6\times 10^{-19}\times 7.69\times 10^{6}\times 9.21\times 10^{-4}}$

$\theta=10.60^{\circ}$

So, the angle between the electron's velocity and the magnetic field is 10.6 degrees. Hence, this is the required solution,

8 0

4 years ago

An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop the loop maneuver. The acceleration

Natali5045456 [20]

The radius of the loop is 18.9 km

Explanation:

When the airplane is at the top of the loop, the pilot experiences two forces:

The force of gravity, acting downward, of magnitude $mg$
The normal reaction exerted by the seat on the pilot, also acting downward, N

Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:

$mg+N = m\frac{v^2}{r}$

where

m is the mass of the pilot

$g=9.8 m/s^2$ is the acceleration of gravity

N is the normal reaction

v = 430 m/s is the speed of the plane

r is the radius of the loop

Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,

N = 0

Therefore the equation becomes

$mg=\frac{mv^2}{r}$

And so we can find the radius of the loop:

$r=\frac{v^2}{g}=\frac{430^2}{9.8}=18.9 \cdot 10^3 m = 18.9 km$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

8 0

3 years ago

An electron enters a region of space containing a uniform 2.71 × 10 − 5 2.71×10−5 T magnetic field. Its speed is 197 197 m/s and

Andrews [41]

Answer:

r = 0.0414mm

F = 757,692.3Hertz

Explanation:

If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as

F = qvBsintheta... 1

Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as

Fc = mv²/r... 2

Equating both forces

F = Fc

qvBsin theta = mv²/r

Since the body enters perpendicular to the field, theta = 90°

The equality becomes;

qvB sin90° = mv²/r

qvB = mv²/r

qB = mv/r

r = mv/qB

Given mass of the electron m = 9.11×10^-31kg

Velocity of the object v = 197m/s

Charge on the electron q = 1.6×10^-19C

Magnetic field B = 2.71×10^-5T

Substituting this value into the equation to get the radius r we have;

r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5

r = 1794.67×19^-31/4.336×10^-24

r = 413.89×10^-7

r = 0.0000414m

r = 0.0414mm

b) Frequency of the motion F = w/2π where w is the angular velocity

Since w = v/r

F = (v/r)/2π

F = v/2πr

F = 197/2π(0.0000414)

F = 757,692.3Hertz

6 0

4 years ago

Explain the following observations:

Deffense [45]

Answer and Explanation:

a. An oxygen-filled balloon is not able to float in the air, because the oxygen inside the balloon is of the same density, that is, the same "weight" as the oxygen outside the balloon and present in the atmosphere. The balloon can only float if the gas inside it is less dense than atmospheric oxygen. Helium gas is less dense than atmospheric gas, so if a balloon is filled with helium gas, that balloon will be able to float because of the difference in density.

b. The ship is able to float in the water because its steel construction is hollow and full of air. This makes the average density of this ship less than the density of water, which makes the ship lighter than water and for this reason, this ship is able to float. In addition, the ship is partially immersed, allowing the weight of the ship on the water to counteract the buoyant force that the water promotes on the ship. Weight and buoyant are two opposing forces that keep the ship afloat.

6 0

3 years ago

A scientist collected data in 10 trials comparing tired students' and awake students' test scores. Trial Tired Average Score Awa

RSB [31]

Scores of trial 2,3 are more accurate while trail 1 is the least precise as well as un-reproducible.

Explanation:

The second rating is really similar to the first since Score 1 is 34 points, 64 points.

They measure the average as 34 + 67/2 = 50.5

Deviations from the defined values are determined as follows:

50.5-34 = 16.5 & 50.5-67 = -16.5

Then the total variance is = (16.5 + -16.5)/2 = 0.00

Calculating Rating 2 by the provided values: 56 percent, 88 percent.

We measure an average of 56 + 88/2 = 72.

Deviations from the specified values are determined as follows: 72-56 = 16, 72-88 =-16.

The maximum variations here are 0.00.

Calculation of Score 3 by the specified values: 60 percent, 90 percent.

Similarly, we will consider the Median as 60 + 90/2 = 75.

Deviations from this are 75-60 = 15, 75-90 = -15.

The maximum variations here are 0.00.

The assigned Score 4 is 58 per cent, 86 per cent and its average is 72 and its deviation is-14, while its average deviation is 0.

Result: Trail 1 has a high divergence, so it is less reliable.

8 0

3 years ago

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