When The rate of effusion is inversely proportional to the √molar mass of the substance. and we have R(He) = 1L / 4.5 min so, R(He)/R(Cl2) = (molar mass of Cl2/ molar mass of He)^0.5 and when we have the molar mass of Cl2 = 70.9 & the molar mass of He = 4 so by substitution: (1L/4.5 min)/ R(Cl2) = (70.9 / 4)^0.5 (1L/4.5 min) / R(Cl2) = 4.21 ∴R(Cl2) = (1L/4.5 min) / 4.21 = 1L/ (4.5*4.21)min = 1 L / 18.945 min ∴Cl2 will take 18.945 min for 1 L to effuse under identical conditions
