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SpyIntel [72]
3 years ago
5

It took 4.5 minutes for 1.0 l helium to effuse through a porous barrier. how long will it take for 1.0 l cl2 gas to effuse under

identical conditions?
Chemistry
1 answer:
serious [3.7K]3 years ago
4 0
When The rate of effusion is inversely proportional to the √molar mass of the substance.
and we have R(He) = 1L / 4.5 min so,
R(He)/R(Cl2) = (molar mass of Cl2/ molar mass of He)^0.5
and when we have the molar mass of Cl2 = 70.9  & the molar mass of He = 4
so by substitution:
(1L/4.5 min)/ R(Cl2) = (70.9 / 4)^0.5
(1L/4.5 min) / R(Cl2) = 4.21
∴R(Cl2) = (1L/4.5 min) / 4.21 = 1L/ (4.5*4.21)min = 1 L / 18.945 min
∴Cl2 will take 18.945 min for 1 L to effuse under identical conditions

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You happen to be visiting Northern California and you are driving by Suisun Bay, a notorious graveyard for old ships. You notice
eduard

Answer:

1) rusting of metal is both chemical and physical change

2) black ice is an example of a physical change

Explanation:

when metal rusts, it is due to a reaction between the atoms in the metal and the atoms in the air(oxygen) or water(oxygen). When it rusts it also physically changes the look of the metal from silver to dirty brownish maroon.

Black ice is a change in state hence it cannot be a chemical change as the original substance NO LONGER EXISTS in a chemical reaction. It is a physical change however as the ice is changing into a different state of matter.

HOPE THIS HELPS!!!

4 0
3 years ago
As of January 2009, the USA has produced 60,000 metric tons of nuclear waste in 60 yesrs of operating 104 nuclear power plants.
goblinko [34]

Answer:  a. 0.8 tons p. month.

Explanation:

Given: Total nuclear waste = 60,000 metric tons

Time take = 60 years = 12 x 60 months   [ 1 year = 12 months]

=  720 months

Total nuclear power plants = 104

Now , Average  waste produced by each plant = \dfrac{\text{Total waste}}{\text{Time x Number of plants}}

=\dfrac{60000}{720\times104}\approx0.8\text{ tons per month.}

Hence, 0.8 tons p. month is produced by each plant.

So, option a. is correct.

5 0
3 years ago
Read 2 more answers
6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/
Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

8 0
3 years ago
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BaLLatris [955]
Bc they dooooooooooooooooooo
4 0
3 years ago
Someone please help me with this ???
Verizon [17]

Answer:

c

Explanation:

6 0
3 years ago
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