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qaws [65]
3 years ago
10

What does one mole of H2O correspond to?

Chemistry
2 answers:
Andrei [34K]3 years ago
8 0

Answer: A

Explanation:

emmasim [6.3K]3 years ago
3 0

Answer:

Its A

Explanation:

Just took the test and got a 100%

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Equation for the for formation of ethanoic acid<br>​
vladimir2022 [97]

Answer:

2 C4H10 + 5 O2 → 4 CH3CO2H + 2 H2O.

Explanation:

Light naphtha components are readily oxidized by oxygen or even air to give peroxides, which decompose to produce acetic acid according to the chemical equation, illustrated with butane .

5 0
3 years ago
When the substance dissolves the solution is not transparent true or false <br>​
bogdanovich [222]

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Some substances dissolve when you mix them with water. When a substance dissolves, it might look like it has disappeared, but in fact it has just mixed with the water to make a transparent (see-through) liquid called a solution.

Explanation:

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2 years ago
NH3 +<br>H2SO4 → __(NH4)2SO4​
Zielflug [23.3K]

Answer:

This is not a balanced equation

Explanation:

Let's make it a balanced equation.

2 NH3 + H2So4 = (NH4)2So4

Glad I could help!!

8 0
3 years ago
Pls help with give brainiest Which statement best explains why the sun's
Alexxandr [17]
It’s B pretty sure it is
4 0
3 years ago
The 10x SDS gel electrophoresis buffer contains 250mM Tris HCl, 1.92M Glycine, and 1% (w/v) SDS. Buffers are always used at 1x c
olchik [2.2K]

Answer:

25 mM Tris HCl and 0.1% w/v SDS

Explanation:

A <em>10X solution</em> is ten times more concentrated than a <em>1X solution</em>. The stock solution is generally more concentrated (10X) and for its use, a dilution is required. Thus, to prepare a buffer 1X from a 10X buffer, you have to perform a dilution in a factor of 10 (1 volume of 10X solution is taken and mixed with 9 volumes of water). In consequence, all the concentrations of the components are diluted 10 times. To calculate the final concentration of each component in the 1X solution, we simply divide the concentration into 10:

(250 mM Tris HCl)/10 = 25 mM Tris HCl

(1.92 M glycine)/10 = 0.192 M glycine

(1% w/v SDS)/10 = 0.1% w/v SDS

Therefore the final concentrations of Tris and SDS are 25 mM and 0.1% w/v, respectively.

7 0
3 years ago
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