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Levart [38]
3 years ago
6

When a point charge of q is placed on one corner of a square, an electric field strength of 2 N/C is observed at the center of t

he square. Suppose three identical charges of q are placed on the remaining three corners of the square. What is the magnitude of the net electric field at the center of the square
Physics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

Explanation:

Net electric field at the centre will be zero .

Since all the charges are equal and they all are symmetrically situated around the centre . So the electric field produced by each will cancel  out each other and hence the resultant electric field will be zero . It happens because electric field is a vector quantity and therefore it adds up vectorially . All the four electric field will form two pairs , in each pair electric fields are acting in opposite direction . So they all cancel out to zero .

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Why does an object in motion stay in motion unless acted on by an unbalanced force?
Svet_ta [14]

Answer: A) because forces are what stop and start motion

Explanation:

From Newton's first law, an object tends to stay in state of rest or motion unless acted upon by an unbalanced external force. This is also known law of inertia. This is because a force can stop or start a motion. A force cause body to accelerate to decelerate otherwise the body continues with constant speed.

7 0
3 years ago
Read 2 more answers
True or false. A solvent is the part of a solution that dissolves the solute
mash [69]

Answer:

True

Explanation:

I'm not exactly sure on this , but A solution is made up of two components. Namely,

1. The solvent

2. The solute

The solute has a lower percentage in the solution while the solvent has a higher percentage in the solution so yes, the solvent is used to dissolve the solute

6 0
3 years ago
A rocket is launched upward with a constant acceleration of 165 m/s^2. After 8.00 seconds of ascension a passenger on the rocket
Novay_Z [31]

To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.

Through the position equations we will calculate the distance traveled.

Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.

For time (t) and acceleration (a) we have to,

t = 8s, a = 165m/s^2

The velocity would be,

u = a*t \\u = 165*8\\u = 1320m/s

Now the position is,

h= \frac{1}{2} at^2

h = \frac{1}{2} 165*8^2

h = 5280m

Now with the initial speed and position found we will have the time is,

h=ut +\frac{1}{2} at^2

-5280=1320t - \frac{1}{2} 9.8t^2

4.9t^2-1320t-5280=0

Solving the polynomian we have,

t = 273.33s = 4.56minutes

Therefore  the rocket will take to hit the ground around to 4.56min

5 0
3 years ago
a student attaches a 0.5 kg object to a 0.7 m string and rotates the object around her head and parallel to the ground. how much
Marina CMI [18]

The object would have a centripetal acceleration <em>a</em> of

<em>a</em> = (12 m/s)² / (0.7 m) ≈ 205.714 m/s²

so that the required tension in the string would be

<em>T</em> = (0.5 kg) <em>a</em> ≈ 102.857 N ≈ 100 N

(rounding to 1 significant digit)

3 0
3 years ago
Starting from rest, a 4.0-kg body reaches a speed of 8.0 m/a in 20 s. What is te net force acting on the body?
Strike441 [17]
The guy below is wrong!


F=ma
Where force = mass x acceleration

We dont have acceleration, a= change in velocity divided by the time taken.
a = v (final velocity) - u (initial) / t
a us 8-0 (at rest means u was 0) / 20 = 0.4

Using F=ma

F= mass x acceleration 
F= 4 x 0.4
F=1.6 N
5 0
3 years ago
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