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Levart [38]
3 years ago
6

When a point charge of q is placed on one corner of a square, an electric field strength of 2 N/C is observed at the center of t

he square. Suppose three identical charges of q are placed on the remaining three corners of the square. What is the magnitude of the net electric field at the center of the square
Physics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

Explanation:

Net electric field at the centre will be zero .

Since all the charges are equal and they all are symmetrically situated around the centre . So the electric field produced by each will cancel  out each other and hence the resultant electric field will be zero . It happens because electric field is a vector quantity and therefore it adds up vectorially . All the four electric field will form two pairs , in each pair electric fields are acting in opposite direction . So they all cancel out to zero .

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Hi there!

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