Answer: Speeding Up
Explanation:
Force is proportional to the acceleration of an object. The greater the force, the more acceleration will be produced.
When the force on the tire is equal to the weight of the car, the car is reaching a stability as a result of increase in motion.
But when the force of the load on the tire is quite large(most likely several times the weight of the car) and is directed forward, then, the car is at high speed.
I think it is -3.99 x 102 j
To solve this problem we will apply the definition of Power and Speed. In turn, we will consider that one gram of carbohydrate, according to numerous scientific studies, contributes around 17kJ of energy. Therefore, if this were true, the total energy of 26 grams would be

Power can be described as the amount of energy applied at a given time, that is,



The speed is described as the distance traveled in a certain time, and its units in international system is m / s, converting and replacing we will have


Now,

The distance is,



Therefore the distance walked is 1610.08m
Answer:
B. Only wavelengths between infrared and ultraviolet
Explanation:
That is the visible spectrum if you look up a diagram of the light spectrum.