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Lunna [17]
3 years ago
13

How is a net electric charge produced?​

Physics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

Net charge produce due to presence of different chargers in the vicinity or in the considered region.

Explanation:

Net electric charge is just a concept introduce to identify the result of the presence of number of charges which interact with each other. It can be found by treating electric chargers in algebraic form like numbers, where +charges get added with +charges

-charges get added with -charges

and when adding two charges with opposite signs they get subtracted and the symbol of the resultant charge comes from the charge with highest magnitude.

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A 60.00-cm guitar string under a tension of 50.000 N has a mass per unit length of 0.100 00 g/cm chegg
Evgen [1.6K]

Fundamental frequency,

f=v2l=T/μ−−−−√2l

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=58.96Hz

Let, n th harmonic is the hightest frequency, then

(58.93)n = 20000

∴N=339.38

Hence, 339 is the highest frequency.

∴fmax=(339)(58.93)Hz=19977Hz.

<h3>What is frequency?</h3>

In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.

learn more about frequency refer:

brainly.com/question/254161

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7 0
2 years ago
You are a member of an alpine rescue team and must project a box of supplies, with mass m, up an incline of constant slope angle
AlekseyPX

Answer:

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

Explanation:

When we push the box from the bottom of the incline towards the top then by work energy theorem we can say that

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here we know that

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also we know that the length of the incline is given as

s = \frac{h}{sin\theta}

now we have

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so we have

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

3 0
3 years ago
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