During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the
1 answer:
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We know density = Mass / Volume
So Volume = Mass/Density
Volume = Area * Thickness
So the approximate thickness of the foil in millimeters =
Answer:
distance r from the uranium atom is 18.27 nm
Explanation:
given data
uranium and iron atom distance R = 44.10 nm
uranium atom = singly ionized
iron atom = doubly ionized
to find out
distance r from the uranium atom
solution
we consider here that uranium electron at distance = r
and electron between uranium and iron so here
so we can say electron and iron distance = ( 44.10 - r ) nm
and we know single ionized uranium charge q2= 1.602 × C
and charge on iron will be q3 = 2 × 1.602 × C
so charge on electron is q1 = - 1.602 × C
and we know F =
so now by equilibrium
Fu = Fi
=
put here k = and find r
=
r = 18.27 nm
distance r from the uranium atom is 18.27 nm