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3 years ago

Please help me with number 2

Mathematics

2 answers:

svetoff [14.1K]3 years ago

5 0

The answer would be A

Nitella [24]3 years ago

4 0

Answer:

option A A is the correct answer of this question

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What is the answer to this question

astra-53 [7]

Answer: I think the answer is B

Step-by-step explanation:

8 0

3 years ago

Jason and his children went into a movie theater where they sell drinks for $4 each and pretzels for $5 each. Jason has $65 to s

klemol [59]

Answer:

Number of drink = 5

Number of pretzel = 9

Step-by-step explanation:

Given:

Cost of each drink = $4

Cost of each pretzel = $5

Total money = 65

Total number of drink and pretzel = 14

Find:

Number of drink and pretzel

Computation:

Number of drink = x

Number of pretzel = 14 - x

So,

x(4) + (14-x)5 = 65

4x + 70 - 5x = 65

x = 5

Number of drink = 5

Number of pretzel = 14 - x

Number of pretzel = 14 - 5 = 9

4 0

3 years ago

Read 2 more answers

Please help me 19 points for whoever answers number 3

Nastasia [14]

15%

amount error is guess subtract actual amount 198-172 = 26
26/172 = 0.15
0.15 x100 = 15%

7 0

3 years ago

Read 2 more answers

Simplify the polynomial (−8x) x (−2x)

harkovskaia [24]

Negative multiplied by a negative is positive
8 multiplied by 2 is 16
x mutiplied by x is equal to x square
combine them all up and you get ......
$16 x^{2}$ is the answer :-)

4 0

3 years ago

Find the volume of the parallelepiped with adjacent edges t = 3j – 4j – 6k, u = 3i – 7j – 7k and v = 5i + j + 3k.

Assoli18 [71]

Answer:

94 cubic units

Step-by-step explanation:

The volume of this parallelepiped (the product of area of its base and height) is equal to the absolute value of the scalar triple product $|\vec{t}\cdot (\vec{u}\times \vec{v})|$

Since

$\vec{t}=3\vec{i}-4\vec{j}-6\vec{k}=(3,-4,-6)\\ \\\vec{u}=3\vec{i}-7\vec{j}-7\vec{k}=(3,-7,-7)\\ \\\vec{v}=5\vec{i}+\vec{j}+3\vec{k}=(5,1,3)$

we have

$|\vec{t}\cdot (\vec{u}\times \vec{v})|=\left|\left|\begin{array}{ccc}3&-4&-6\\3&-7&-7\\5&1&3\end{array}\right|\right|=|3\cdot (-7)\cdot 3+(-4)\cdot (-7)\cdot 5+3\cdot 1\cdot (-6)-5\cdot (-7)\cdot (-6)-3\cdot (-7)\cdot 1-3\cdot (-4)\cdot 3|=|-63+140-18-210+21+36|=|-94|=94\ un^3.$

4 0

3 years ago