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Neporo4naja [7]
3 years ago
11

g A mass of 2.0 kg traveling at 3.0 m/s along a smooth, horizontal plane hits a relaxed spring. The mass is slowed to zero veloc

ity when the spring has been compressed by 0.15 m. What is the spring constant of the spring
Physics
1 answer:
dezoksy [38]3 years ago
8 0

By the work-energy theorem, the total work done on the mass by the spring is equal to the change in the mass's kinetic energy:

<em>W</em> = ∆<em>K</em>

and the work done by a spring with constant <em>k</em> as it gets compressed a distance <em>x</em> is -1/2 <em>kx</em> ²; the work it does is negative because the restoring force of the spring points opposite the direction in which it's getting compressed.

So we have

-1/2 <em>k</em> (0.15 m)² = 0 - 1/2 (2.0 kg) (3.0 m/s)²

Solve for <em>k</em> to get <em>k</em> = 800 N/m.

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