$(f-g)(x)=f(x)(x)\\\\\text{substitute}\ f(x)=4x^2+1\ \text{and}\ g(x)=x^2-5\\\\(f-g)(x)=(4x^2+1)-(x^2-5)=4x^2+1-x^2-(-5)=4x^2+1-x^2+5\\\\\text{combine like terms}\\\\(f-g)(x)=(4x^2-x^2)+(1+5)=3x^2+6$

6 0

3 years ago

The cheerleading squad at Oxford High School had 20 members with the old coach. Now, with the new coach, there are 25 members on

Iteru [2.4K]

(I’m not completely sure)

(25 - 20) (divided by) 20 x 100
Is the formula for percentage increase

The answer would be 25%

3 0

3 years ago

What value of “n” makes the equation true?

Doss [256]

Answer:

12 OR 1/12 (Check how you write your equations! Just look below for the one that it actually is lol)

Step-by-step explanation:

6 = (1/2)n

6/(1/2) = n

12 = n

6 = 1/(2n)

6(2n) = 1

12n = 1

n = 1/12

6 0

2 years ago