The answer is 5000 ft
His displacement is actually the hypotenuse (c) of the triangle with sides 6 blocks and 8 blocks.
According to the Pythagorean theoreme:
c² = a² + b²
c² = 6² + 8²
c² = 36 + 64
c² = 100
c = √100
c = 10 blocks
Since 1 block is 500ft long, then 10 blocks are 5000 ft long:
1 : 500ft = 10 : x
x = 10 * 500ft / 1 = 5000 ft
The answer is 27.29 trust
Answer:
A) 6,3
Why?
The midpoint, which is somewhat self-explanatory thanks to its name, is a point in the center of a line.
To answer this question properly, you need to analyze the line and assess the situation.
How did it go from x = 2 to x = 10? Let's see, if we count by two's across the line, you'll notice it makes more sense. So now we know that every square goes up by two. x = 6 is the exact center of the line.
I hope this wasn't confusing, it's tough to explain it!
Answer:
a)
degrees
b) 
Step-by-step explanation:
An approximate formula for the heat index that is valid for (T ,H) near (90, 40) is:

a) Calculate I at (T ,H) = (95, 50).
degrees
(b) Which partial derivative tells us the increase in I per degree increase in T when (T ,H) = (95, 50)? Calculate this partial derivative.
This is the partial derivative of I in function of T, that is
. So


