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poizon [28]
3 years ago
12

Suppose you put an ice cube into a cup of hot tea. In what direction does energy in the form of heat flow? What happens to the i

ce cube as this flow of energy occurs?
Physics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

The energy flows between the ice and the tea equally. The table below shows the temperatures of several different objects made of the same material.

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A rope pulls a 82.5 kg skier at a constant speed up a 18.7° slope with μk = 0.150. How much force does the rope exert?
Artist 52 [7]

Answer:

374 N

Explanation:

N = normal force acting on the skier

m = mass of the skier = 82.5

From the force diagram, force equation perpendicular to the slope is given as

N = mg Cos18.7

μ = Coefficient of friction = 0.150

frictional force is given as

f = μN

f =  μmg Cos18.7

F = force applied by the rope

Force equation parallel to the slope is given as

F - f - mg Sin18.7 = 0

F - μmg Cos18.7 - mg Sin18.7 = 0

F = μmg Cos18.7 + mg Sin18.7

F = (0.150 x 82.5 x 9.8) Cos18.7 + (82.5 x 9.8) Sin18.7

F = 374 N

6 0
3 years ago
2. How can we make the percent error value as minimal as possible?
andriy [413]

Answer:

Percent error can be reduced by improving both your accuracy and precision.

8 0
3 years ago
Read 2 more answers
How would you classify an EM wave with a frequency of 10^7 Hz?
tiny-mole [99]

Answer:

I think it is television and radio wave

5 0
2 years ago
A 1500-W heater is connected to a 120-V line for 2.0 hours. How much heat energy is produced?
weeeeeb [17]
<span>A joule is equal to one watt per second and so we must find out how many seconds are in two hours. A shortcut you can use is remove the zeros and multiplying the remaining numbers before adding the the zeros back to the total of your result 6 x 6 x 2 = 72 and thus 60 x 60 x 2 = 7200 72 x 15 = 1080 and thus 7200 x 1500 = 10800000 joules one mega joule equals one million joules So we can simplify things and say 10.8 MJ</span>
3 0
2 years ago
A certain wire has a resistance R. What is the resistance of asecond wire, made of the same material, that is half as long and h
Gekata [30.6K]

Given:

<em>Resistance = R </em>

<em>Lenght of second wire (L2)= half of the first wire's lenght (L1) = L1/2</em>

<em>Diameter of the second wire (D2)= Half of the first wire's diameter(D1) = D2/2</em>

Apply:

R=\frac{\rho L}{A}

Where:

R= resistance

ρ= resitivity

L= lenght

A = cross sectional area

Replacing:

R = ρL2/A2

R= ρ (L1/2)/ (πd2^2 /4 )

R= 2ρL / π (d/2)^2

R= 2ρL / [πd^2/4]

R=2 ( 4ρL/πd^2)

R= 2R

Answer = 2R

4 0
10 months ago
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