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Nezavi [6.7K]
3 years ago
7

A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts

for 1.85 ms, which results in a velocity of 37.0 m/s in the opposite direction. What was the magnitude of the horizontal force
Physics
1 answer:
Viefleur [7K]3 years ago
8 0

Answer:

4987N

Explanation:

Step 1:

Data obtained from the question include:

Mass (m) = 0.140 kg

Initial velocity (U) = 28.9 m/s

Time (t) = 1.85 ms = 1.85x10^-3s

Final velocity (V) = 37.0 m/s

Force (F) =?

Step 2:

Determination of the magnitude of the horizontal force applied. This can be obtained by applying the formula:

F = m(V + U) /t

F = 0.140(37+ 28.9) /1.85x10^-3

F = 9.226/1.85x10^-3

F = 4987N

Therefore, the magnitude of the horizontal force applied is 4987N

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Semmy [17]

14m/s

Explanation:

Given parameters:

Height of the ball = 10m

Unknown:

Velocity of fall or final velocity = ?

Solution:

We are going to use the appropriate equation of motion to solve this problem.

The object is falling with respect to gravity.

  V² = U² + 2gH

where V is the final velocity

            U is the initial velocity

             g is the acceleration due to gravity 9.8m/s²

             H is the height of fall

The initial velocity here is zero and

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learn more:

Motion problems brainly.com/question/5248528

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3 years ago
How can we predict how high a roller coaster can go knowing its velocity?
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If a current­-carrying wire has a cross­-sectional area that gradually becomes smaller along the length of the wire, the drift v
jarptica [38.1K]

Answer:d

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Drift velocity is given by

v_d=\frac{I}{n\times Q\times A}

where v_d=drift velocity

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If area of cross-section decreases gradually then drift velocity will increase because drift velocity is inversely proportional to Area of cross-section

       

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A person weighing 0.9 kN rides in an elevator that has a downward acceleration of 1.9 m/s^2. The acceleration of gravity is 9.8
Keith_Richards [23]

Answer:

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Explanation:

The elevator floor acts on the person with a force that is due to the gravitational acceleration less the downward acceleration of the elevator:

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in other words, considering the elevator floor as a reference frame in the Earth's gravitational field, the person's weight decreases due to the downward acceleration, as follows:

F = m\cdot(g-a)

We are given the person's weight at rest, 0.9kN, from which the mass can be determined as:

900 N = m\cdot g \implies m = \frac{900N}{9.8 \frac{m}{s^2}}

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F = \frac{900N}{9.8 \frac{m}{s^2}}\cdot(9.8-1.9)\frac{m}{s^2}\approx 725.5N=0.7255kN

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When cattle are processed, the most likely use for the animals' skin is in

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The commonly used animals in leather production is however cattle and

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