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mezya [45]
3 years ago
10

A copper wire has a square cross section 2.1 mm on a side. The wire is 4.3 m long and carries a current of 3.6 A. The density of

free electrons is 8.5 * 1028>m3 . Find the magnitudes of (a) the current density in the wire and (b) the electric field in the wire. (c) How much time is required for an electron to travel the length of the wire?

Physics
1 answer:
aleksley [76]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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What do we mean by primitive material? How can we tell if a meteorite is primitive?
zimovet [89]

Answer:

Primitive material was formed in the early stage of the solar system, before planets cooled off enough to differentiate elements of different density. It was not subject to great heat or pressure after it formed.

We can identify primitive meteorites by their composition, primitive meteorites are usually undifferentiated stones, with some metallic grains mixed in. Some primitive meteorites are darker, carbonaceous stones.

4 0
3 years ago
5. If the total charge of an atom's nucleus is +3 and the total charge of the surrounding electrons is -3, the atom
tekilochka [14]

Answer:

i believe the answer is d.

Explanation:

its either d or its c. but based off of the fact the it is the only one with a positive charge and the one around it are negative then its most likely d.

8 0
4 years ago
Lightweight, vertically suspended spiral spring with a spring constant of 8.6 N / m is fitted with 64 g weight. The weight shall
alexandr1967 [171]

Answer:

Explanation:

Given that

Force constant k=8.6N/m

Weight =64g=64/1000=0.064kg

Extension is 45mm=45/1000= 0.045m

It will have it highest spend when the Potential energy is zero

Therefore energy in spring =change in kinetic energy

Ux=∆K.e

½ke² = ½mVf² — ½mVi²

Initial velocity is 0, Vi=0m/s

½ke² = ½mVf²

½ ×8.6 × 0.045² = ½ ×0.064 ×Vf²

0.0087075 = 0.032 Vf²

Then, Vf² = 0.0087075/0.032

Vf² = 0.2721

Vf=√0.2721

Vf= 0.522m/s

The time it will have this maximum velocity?

Using equation of motion

Vf= Vi + gr

0.522= 0+9.81t

t=0.522/9.81

t= 0.0532sec

t= 53.2 milliseconds

5 0
3 years ago
A spaceship from a friendly, extragalactic planet flies toward Earth at 0.201 times the speed of light and shines a powerful las
bagirrra123 [75]

Answer:

The wavelength of observed light on earth is 568.5 nm

Explanation:

Given that,

Velocity of spaceship v= 0.201c

Wavelength of laser \lambda= 697\ nm

We need to calculate the wavelength of observed light on earth

Using formula of wavelength

\lambda_{0}=\lambda_{e}\times\sqrt{\dfrac{1-\dfrac{v}{c}}{1+\dfrac{v}{c}}}

\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-\dfrac{0.201 c}{c}}{1+\dfrac{0.201c}{c}}}

\lambda_{0}=697\times10^{-9}\times\sqrt{\dfrac{1-0.201}{1+0.201}}

\lambda=5.685\times10^{-7}\ m

\lambda=568.5\times10^{-9}\ m

\lambda=568.5\ nm

Hence, The wavelength of observed light on earth is 568.5 nm

8 0
3 years ago
Determine the Ka value of propanoic acid if it is found that 2.95x10-3 M of each conjugate exists when a 0.65 M solution is made
MrRa [10]

Answer:

1.34 × 10⁻⁵

Explanation:

Let's consider the acid dissociation of propanoic acid.

CH₃CH₂COOH(aq) + H₂O(l) ⇄ CH₃CH₂COO⁻(aq) + H₃O⁺(aq)

We can find the acid dissociation constant (Ka) using an ICE chart.

      CH₃CH₂COOH(aq) + H₂O(l) ⇄ CH₃CH₂COO⁻(aq) + H₃O⁺(aq)

I                 0.65                                           0                       0

C                  -x                                            +x                      +x

E               0.65 - x                                       x                        x

We know that [CH₃CH₂COO⁻] = [H₃O⁺] = x = 2.95 × 10⁻³ M

[CH₃CH₂COOH] = 0.65 - 2.95 × 10⁻³ = 0.64705 M

Ka = [CH₃CH₂COO⁻].[H₃O⁺]/[CH₃CH₂COOH]

Ka = (2.95 × 10⁻³)²/0.64705

Ka = 1.34 × 10⁻⁵

6 0
3 years ago
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