Answer:
television
Explanation:
a television refracts light (the light bounces off of the screen
The maxiumum strength of the induced electric field in the capacitor that uses thick paper as dielectric material is 16 x 10⁶ V/m.
<h3>
What is maximum electric field strength?</h3>
The maximum electric field strength above which an insulating material begins to break down and conduct is called its dielectric strength.
The dielelectric strength of paper is given as;
E = 16 MV/m = 16 x 10⁶ V/m
Thus, the maxiumum strength of the induced electric field in the capacitor that uses thick paper as dielectric material is 16 x 10⁶ V/m.
Learn more about dielectric strength here: brainly.com/question/27017570?source=archive
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Answer:
The magnitude of electric force on object B due to object A when they are 2r distance apart is F/4.
Explanation:
Given :
Electric charge on object A = +Q
Electric charge on object B = +4Q
When the objects A and B are r distance apart, the magnitude of electrostatic force exerted on B due to A is given by the relation :
.....(1)
Now, the two objects are apart by distance of 2r, hence the force acting on the object B due to A is :


Substitute equation (1) in the above equation.

Answer:
2726.54 J/K
Explanation:
Entropy change = 
where
m = mass of water = 450g = 0.45kg
= 2.26 MJ/kg = 2260000 J/kg
T = temperature at which water change from liquid to steam = 100 degree Celsius = 272 + 100 = 373 degree kelvin.
Entropy change =
= 2726.54 J/K
Answer:
3) From 37 km/h to 47 km/h
Explanation:
Kinetic Energy: This is the energy posses by a body in motion. The Unit of kinetic energy is joules. And it is expressed mathematically as,
Ek = 1/2mv².................... Equation 1
ΔEk = 1/2m(v₂² - v₁²)...................... Equation 2
Where ΔEk = change in kinetic energy, m = mass of the body, v₁ = initial velocity, v₂ = final velocity of the body.
<em>Note: The mass of the car is constant in both cases.</em>
When the body accelerate from 27 kh/h to 37 km/h
ΔEk₁ = 1/2m(37²-27²)
ΔEk₁ = 1/2m(640)
ΔEk₁ = 320m J.
When The body accelerate from 37 km/h to 47 km/h
ΔEk₂ = 1/2m(37²-47²)
ΔEk₂ = 1/2m(840)
ΔEk₂ = 420m J
From the above,
ΔEk₂ > ΔEk₁.
Hence the correct option is 3) From 37 km/h to 47 km/h