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mezya [45]
3 years ago
10

A copper wire has a square cross section 2.1 mm on a side. The wire is 4.3 m long and carries a current of 3.6 A. The density of

free electrons is 8.5 * 1028>m3 . Find the magnitudes of (a) the current density in the wire and (b) the electric field in the wire. (c) How much time is required for an electron to travel the length of the wire?

Physics
1 answer:
aleksley [76]3 years ago
4 0

Explanation:

Below is an attachment containing the solution.

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Energy energy can be transferred from one form to another we use many Indrajeet Converse in our daily life observe carefully to
aleksandr82 [10.1K]

Answer:

Find the list below.

Explanation:

Energy conversion imply the transformation of energy from one form to another. Examples of these conversions in my home include the following:

1. Chemical energy stored in food is converted to mechanical energy used in working(example sweeping)

2. Chemical energy stored in batteries are used to produce sound energy from the radio.

3. Electrical energy flowing through the wires are used to provide heat energy from the heating device.

4. Electric energy stored in the fan is converted to kinetic energy.

5. Chemical energy stored in petrol is converted to mechanical and electrical energies in the generator.

6. Electric energy supplied by the electric gas cooker is used to generate thermal energy after heating water.

7. Electrical energy flowing through the wires supply light energy in the bulbs.

8. Electric energy is converted to light and sound energy in the televisions.

9. Light energy from the sun is converted to chemical energy in the plants at the garden.

10. Electric energy is converted to sound and light energy in the kitchen blender.

3 0
3 years ago
A car has a kinetic energy of 41.6 kJ.
musickatia [10]
K=1/2 mv2

M=?

41.6kj convert to joules by multiplying by 1000 so it will be 41,600J because the unit of kinetic energy is in joules.

41,600=1/2(m)(8)

Arrange the equation it will be:

M= 41,600/4 = 10,400

Final answer is:
m= 10,400 kg
4 0
2 years ago
Name a device or gadget that converts
GrogVix [38]

Answer:

a heat engine converts heat to mechanical energy.

electric generator

7 0
3 years ago
From a hot air balloon 2 km​ high, a person looks east and sees one town with angle of depression of 16 degrees. He then looks w
Dafna1 [17]

Answer:

7km

Explanation:

The angle of depression is congruent to the angle of elevation and can be explained as angle below horizontal in which the person observing an object must view for him/her to view object's that are lower than him/her.

In angle of depression, there is assumption that object is closer to the person observing it, so there is parallel horizontal for both observing and object been observed.

hot air balloon 2 km​ high,

there exist two triangles

From trigonometry

Tanx= opposite/adjacent

Opp= 2km

Adj= X1

first triangle have base length of

Tan(16)=2/X1

X1=2/ tan(16)

X1=6.97

For Second triangle

Tanx= opposite/adjacent

Opp= 2km

Adj= X2

the other with a base length of

X2=2/tan(84)

X2=0.21

Therefore,, the total distance between the two towns is

x1+x2=6.97+0.21=7.18km

6 0
3 years ago
A mysterious rocket-propelled object of mass 49.5 kg is initially at rest in the middle of the horizontal, frictionless surface
Romashka-Z-Leto [24]

The distance covered by the rocket in the first 5 seconds is 7.13 m

Explanation:

In order to solve the problem, we have to find the acceleration of the rocket. We can do it by using Newton's second law, which states that the net force on the rocket is equal to the product between its mass (m) and its acceleration (a):

F(t)=ma(t)

Where here we have:

F(t)=16.8t is the time-dependent force

m = 49.5 kg is the mass

Solving for a(t),

a(t)=\frac{F(t)}{m}=\frac{16.8t}{49.5}=0.34t[m/s^2]

This is the time-dependent acceleration of the rocket.

By integrating this expression, we  find the velocity of the rocket at time t:

v(t)=\int a(t)dt=\int (0.34t)dt=\frac{0.34t^2}{2}=0.17t^2

where we didn't add the constant term since the velocity at t = 0 is zero (the rocket starts from rest).

By integrating this expression, we then find an expression for the position of the rocket at time t:

x(t)=\int v(t) dt = \int (0.17t^2)dt=\frac{0.17t^3}{3}=0.057t^3

Therefore, the distance covered by the rocket in the first t = 5.00 s is:

x(5)=0.057(5.0)^3=7.13 m

Learn more aboiut force and acceleration:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
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