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katen-ka-za [31]
3 years ago
14

Can someone please explain the conservation of momentum? I want to be a rocket scientist lol

Physics
1 answer:
Lostsunrise [7]3 years ago
4 0
The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
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What is the relationship between the poles of a magnet? which direction does the magnet field move?
Assoli18 [71]
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South Pole and North Pole connect.
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3 years ago
How long does it take an airplane to fly 5000 miles if it maintains a speed of 240 miles per hour
aliina [53]
With a 30 mph head wind it takes the plane 18.52 hours to fly 5000 miles. ANSWER 2: With a 30 mph tail wind it takes the plane 15.15 hours to fly 5000 miles.
3 0
3 years ago
Action-reaction forces are not balanced forces because of what?
lara [203]

Oh but they are !

Newton's 3rd law of motion says that for every action, the <em><u>re</u></em>action is
equal and opposite.  That's as balanced as you can get.


4 0
3 years ago
Which best supports the idea that the surface of the moon has changed very little?
likoan [24]
The correct answer is<span> c) Because the moon has no atmosphere, it is not possible for geologic events to occur on the moon.

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8 0
3 years ago
A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa
Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

\phi=\cos^{-1}(Power\ factor)

Put the value into the formula

\phi=\cos^{-1}(0.6)

\phi=53.13^{\circ}

Put the value of Φ in equation (I)

Q=600\tan(53.13)

Q=799.99\ kVAR

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

Q'=600\tan(0.95)

Q'=9.94\ KVAR

We need to calculate the difference between Q and Q'

Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

Q''=790.05\ KVAR

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0
3 years ago
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