Complete Question
A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?
Answer:
The pumpkin's vertical displacement is 
The pumpkin's vertical velocity when it hits the ground is 
Explanation:
From the question we are told that
The horizontal speed is 
The horizontal distance traveled is 
The horizontal distance traveled is mathematically represented as
Where t is the time taken
substituting values
=> 
Now the vertical displacement is mathematically represented as
now the vertical velocity before the throw is zero
So
Now the final vertical velocity is mathematically represented as
substituting values
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Answer:
the answer is
Explanation:
constant acceleration
because when the object's velocity is changing then the object is accelerating or decelerating
as acceleration describe changing of velocity so the answer is constant acceleration
Acceleration is defined as the rate of change of velocity.
Acceleration = (Change in velocity) / time taken
Acceleration = (Final velocity - initial velocity) / time
As the object velocity changes by the same amount in each second, it means the acceleration is constant.
Hope I can help u
Answer:
20.85 years
Explanation:
2.61 km = 2610 m
2.07 kW = 2070 W
First we need to calculate the potential energy required to take m = 
kg of rain cloud to an altitude of 2610 m is
With a P = 2070 W power pump, this can be done within a time frame of
or 658037739/(60*60) = 182788 hours or 182788 / 24 = 7616 days or 7616 / 365.25 = 20.85 years
Answer:
The magnitude of the acceleration of the boy toward the girl is 
Explanation:
It is given that,
Mass of the boy, 
Mass of the girl, 
The acceleration of the girl toward the boy is, 
To find,
The acceleration of the boy toward the girl.
Solution,
Let 
is the magnitude of the acceleration of the boy toward the girl. We know that force acting on one object to other are equal in magnitude but opposite in direction. So,
So, the magnitude of the acceleration of the boy toward the girl is
