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2 years ago

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A gas has an initial volume o.25m^3, and absolute pressure 100kPa. Its initial temperature is 290k. The gas is compressed into a

volume of o.O5m^3 during which its temperature rises to 405k. Calculate its final pressure using the formula . P1V1/T1=p2V2/t2

1 answer:

dezoksy [38]2 years ago

5 0

Answer:

<h2>698.3Kpa</h2>

Explanation:

Step one:

given data

V1=0.25m^3

T1=290k

P1=100kPa

V2=0.5m^2

T2=405k

P2=? final pressure

Step two:

The combined gas equation is given as

P1V1/T1=P2V2/T2

Substituting we have

(100*0.25)/290=P2*0.05/405

25/290=0.5P2/405

0.086=0.05P2/405

cross multiply

0.086*405=0.05P2

34.9=0.05P2

divide both sides by 0.05

P2=34.9/0.05

P2=698.3Kpa

<u>Therefore the new pressure is 698.3Kpa when the gas is compressed</u>

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3 years ago

A car accelerates from rest with an acceleration of 5 m/s^2. The acceleration decreases linearly with time to zero in 15 s, afte

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Integrating both sides we get

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Now since car starts from rest thus at time t = 0 ; v=0 thus c=0

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$\int \frac{dx}{dt}dt=\int (5t-\frac{5t^{2}}{30})dt\\\\x(t)=\frac{5t^{2}}{2}-\frac{5t^{3}}{90}+D$

Now let us assume that car starts from origin thus D=0

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$x(15)=2.5\times 15^{2}-\farc{15^{3}}{18}=375m$

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2 years ago

The pressure of a gas in a rigid container is 125kpa at 300k, what we be the new pressure if the temperature increases to 900k

kipiarov [429]

Answer:

375 KPa

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 125 KPa

Initial temperature (T₁) = 300 K

Final temperature (T₂) = 900 K

Final pressure (P₂) =?

The new (i.e final) pressure of the gas can be obtained as follow:

P₁/T₁ = P₂/T₂

125 / 300 = P₂ / 900

Cross multiply

300 × P₂ = 125 × 900

300 × P₂ = 112500

Divide both side by 300

P₂ = 112500 / 300

P₂ = 375 KPa

Thus, the new pressure of the gas is 375 KPa

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2 years ago

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Soloha48 [4]

Answer:

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Explanation:

Given data:

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$57.5 \times 10^3 = \dot m ( \frac{20^2}{2} + 25 \times 9.81 + 101325 \frac{1}{780})$

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so radius = 0.045 m

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3 years ago