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iogann1982 [59]
4 years ago
12

Are spheroidized steels considered as composite? If so, what is the dispersed phase a)- No b)- Yes, Chromium Carbides c)- Yes, I

ron Carbides d)- Yes, Intermetallic Compounds
Engineering
1 answer:
Kruka [31]4 years ago
3 0

Answer: c)-Yes, spheroidized steel are considered as composite.the dispersed phase is  iron carbide.

Explanation: Spheroidized steel are the alloy that have iron as the basic part that have been heat treated to increase their ductility and malleability property .They are considered as composite because they are made up of  iron alloys.  The heat treatment is usually for the carbon steel and so the dispersed phase that is obtained is iron carbide.

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________ is not within other loop.Immersive Reader
djyliett [7]

Answer:

I think node

Explanation:

thank you

have a great day

8 0
3 years ago
can you translate this me gusta el queso :sorry i would have put 300 points buut i used them all for my last question
Irina-Kira [14]
Translate in Spanish: lo siento, hubiera puesto 300 puntos pero los usé todos para mi última pregunta



If you meant a different language lmk
4 0
3 years ago
This test should be performed on all cord sets, receptacles that aren't part of a building or structure's permanent wiring, and
vova2212 [387]

Answer:

A continuity test

Explanation:

A continuity test is used to verified that current will flow in an electrical circuit, it performed by placing a small voltage across the chosen path. continuity test ensure that the equipment grounding conductor is electrically continuous and this test is perform on all the cord sets, receptacles that aren't part of a building or structure's permanent wiring, and cord-and-plug connected equipment required to be grounded. example of equipment used in testing current flow in continuity test are Analog multi-meter, voltage/continuity tester etc.

Continuity test and terminal connection test are the two test required by OSHA on all electrical equipment

8 0
3 years ago
A 600-MW steam power plant, which is cooled by a nearby river, has a thermal efficiency of 56 percent. Determine the rate of hea
Agata [3.3K]

Answer:

471.43MW

Explanation:

the rate of heat transfer to the power plant is determined from the thermal efficiency equation

Qh = \frac{Wout}{nth}

Qh = 600 MW / 0.56

Qh =1071.43MW

The rate of heat transfer to the river is determined from the first law related to heat engine

QL = Qh - Wout

= 1071.43 - 600

= 471.43MW

the heat will be lost to the surrounding air as it passes through pipes and other surrounding components

4 0
3 years ago
assume a five layer network model. There are 700 bytes of application data. There is a 20 bye header at the transport layer, a 2
amm1812

Answer: The overhead percentage is 7.7%.

Explanation:

We call overhead, to all those bytes that are delivered to the physical layer, that don't carry real data.

We are told that we have 700 bytes of application data, so all the other bytes are simply overhead, i.e. , 58 bytes composed by the transport layer header, the network layer header, the 14 byte header at the data link layer and the 4 byte trailer at the data link layer.

So, in order to assess the overhead percentage, we divide the overhead bytes between the total quantity of bytes sent to the physical layer, as follows:

OH % = (58 / 758) * 100 = 7.7 %

4 0
3 years ago
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