All categories

3 years ago

HELP IT WOULD MEAN A LOT IT'S DUE TODAY IN 7 MINUTES

Mathematics

1 answer:

vodka [1.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

39 + 32 = 71

hope this helps have a good day!!

PLEASE MARK BRAINLIEST!! :)

You might be interested in

Which model represents a fraction greater than 3/5?

Olin [163]

Answer:

The last one is your answer :))

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box

pantera1 [17]

To find the z-score for a weight of 196 oz., use

$z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2$

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0

3 years ago

The box-and-whisker plot below shows the age distribution of people at a family reunion.

Wewaii [24]

Answer: answer is c

Step-by-step explanation: quizlet

4 0

3 years ago

Q‒1. [5×4 marks] a) How many three-digit numbers can be formed from the digits 0, 1, 2, 3, 4, 5, and 6? (150) b) How many three-

amid [387]

Answer:

a) 294

b) 180

c) 75

d) 174

e) 105

Step-by-step explanation:

I assume that for each problem, the first digit can't be 0.

a) There are 6 digits that can be first, 7 digits that can be second, and 7 digits that can be third.

6×7×7 = 294

b) This time, no digit can be used twice, so there are 6 digits that can be first, 6 digits that can be second, and 5 digits that can be third.

6×6×5 = 180

c) Again, each digit can only be used once, but this time, the last digit must be odd.

If only the last digit is odd, there are 3×3×3 = 27 possible numbers.

If the first and last digits are odd, there are 3×4×2 = 24 possible numbers.

If the second and last digits are odd, there are 3×3×2 = 18 possible numbers.

If all three digits are odd, there are 3×2×1 = 6 possible numbers.

The total is 27 + 24 + 18 + 6 = 75.

d) If the first digit is 3, and the second digit is 3, there are 1×1×6 = 6 possible numbers.

If the first digit is 3, and the second digit is greater than 3, there are 1×3×7 = 21 possible numbers.

If the first digit is greater than 3, there are 3×7×7 = 147 numbers.

The total is 6 + 21 + 147 = 174.

e) If the first digit is 3, and the second digit is greater than 3, then there are 1×3×5 = 15 possible numbers.

If the second digit is greater than 3, there are 3×6×5 = 90 possible numbers.

The total is 15 + 90 = 105.

6 0

3 years ago

If p is directly proportional to q, and p=9 when q=7.5, find q when p=24.

pishuonlain [190]

<h3>Solution and Explanation:</h3>

If $p$ and $q$ are directly proportional, then they must have a common scalar.

To find $q$ we must first find its scalar. If we let $a$ be the scalar we can form the equation, $ap = q$ .

We are given the information that if $q = 7.5$ then $p = 9$ . We can use that in finding the scalar.

$a \times 9 = 7.5 \\ \frac{a \times 9}{9} = \frac{7.5}{9} \\ a = \frac{75}{90} \\ a = \frac{15}{18}$

Now we can solve for $q$ when $p = 24$ knowing that our scalar is $\frac{15}{18}\\$ .

$ap = q \\ \frac{15}{18} \times 24 = q \\ \frac{360}{18} = q \\ 20 = q$

<h3>Answer:</h3>

$q = 20$ when $p = 24$

4 0

3 years ago

HELP IT WOULD MEAN A LOT IT'S DUE TODAY IN 7 MINUTES​

HELP IT WOULD MEAN A LOT IT'S DUE TODAY IN 7 MINUTES